제출 #374606

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
374606		vishesh312	곤돌라 (IOI14_gondola)	C++17	60 / 100	38 ms	5740 KiB

gondola

#include "bits/stdc++.h"
using namespace std;
#include "gondola.h"

int valid(int n, int arr[]) {
    map<int, bool> mp;
    vector<int> v(arr, arr+n);
    auto it = min_element(v.begin(), v.end());
    rotate(v.begin(), it, v.end());
    for (int i = 0; i < n; ++i) {
        if (mp[v[i]]) return 0;
        mp[v[i]] = true;
        if (v[i] <= n and i != v[i] - v[0]) return 0;
    }
    return 1;
}

int replacement(int n, int a[], int b[]) {
    vector<int> v(a, a+n);
    auto it = min_element(v.begin(), v.end());
    int mn = *it, pos = it - v.begin(), mx = *max_element(v.begin(), v.end());
    rotate(v.begin(), v.begin() + (pos - mn%n + 1 + n) % n, v.end());
    map<int, int> mp;
    for (int i = 0; i < n; ++i) {
        mp[v[i]] = i+1;
    }
    for (int i = n+1; i <= mx; ++i) {
        if (mp.count(i)) b[i-n-1] = mp[i];
        else {
            b[i-n-1] = mp[mx];
            mp[mx] = i;
        }
    }
    return mx - n;
}

using ll = long long;
const ll mod = 1e9+7;
#define sz(x) (int)x.size()

ll binexp(ll a, ll b) {
    if (b == 0) return 1;
    if (b&1) return binexp(a, b-1) * a % mod;
    ll x = binexp(a, b/2);
    return x * x % mod;
}

int countReplacement(int n, int a[]) {
    vector<int> v(a, a+n);
    auto it = min_element(v.begin(), v.end());
    rotate(v.begin(), it, v.end());
    vector<int> v2 = v;
    sort(v2.begin(), v2.end());
    for (int i = 0; i < n-1; ++i) {
        if (v2[i] == v2[i+1]) return 0;
    }
    for (int i = 0; i < n; ++i) {
        if (v[i] <= n and i != v[i] - v[0]) return 0;
    }
    ll ans;
    if (v2[0] > n) ans = n;
    else ans = 1;
    vector<int> bigger;
    bigger.push_back(n);
    for (int i = 0; i < n; ++i) if (v[i] > n) bigger.push_back(v[i]);
    sort(bigger.begin(), bigger.end());
    for (int i = 1; i < sz(bigger); ++i) {
        ans = (ans * binexp(sz(bigger) - i, bigger[i] - bigger[i-1] - 1)) % mod;
    }
    int ret = ans;
    return ret;
}

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 10 / 10
• Subtask 4: 5 / 5
• Subtask 5: 10 / 10
• Subtask 6: 20 / 20
• Subtask 7: 5 / 5
• Subtask 8: 0 / 15
• Subtask 9: 0 / 15
• Subtask 10: 0 / 10