제출 #372571

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
372571		iliccmarko	슈퍼트리 잇기 (IOI20_supertrees)	C++14	0 / 100	1 ms	364 KiB

supertrees

#include <bits/stdc++.h>
#include "supertrees.h"
using namespace std;
#define ll long long
#define endl "\n"
#define INF 1000000000
#define LINF 10000000000000000000LL
#define pb push_back
#define all(x) x.begin(), x.end()
#define len(s) (int)s.size()
#define test_case { int t; cin>>t; while(t--)solve(); }
#define single_case solve();
#define line cerr<<"----------"<<endl;
#define ios { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cerr.tie(NULL); }
#define mod 1000000007LL
const int N = 1005;
int parent[N], s[N];

int find_parent(int u)
{
    while(parent[u]!=u)
    {
        parent[u] = parent[parent[u]];
        u = parent[u];
    }
    return u;
}

void dsu(int u, int v)
{
    u = find_parent(u);
    v = find_parent(v);
    if(u!=v)
    {
        if(s[u]<s[v]) swap(u, v);
        s[u] += s[v];
        parent[v] = u;
    }
}


int construct(vector<vector<int> > p)
{
    int n = len(p);
    for(int i = 0;i<n;i++) parent[i] = i, s[i] = 1;
    for(int i = 0;i<n;i++)
        for(int j = 0;j<n;j++) if(p[i][j]==3||p[i][i]!=1) return 0;
    for(int i = 0;i<n;i++)
        for(int j = 0;j<n;j++) if(p[i][j]==1) dsu(i, j);
    vector<int> r;
    vector<int> rr(n, 0);
    vector<vector<int> > res(n, vector<int>(n, 0));
    for(int i = 0;i<n;++i) {
        int x = find_parent(i);
        if(x==i) r.pb(i), rr[i] = 1;
        else res[i][x] = res[x][i] = 1;
    }
    for(int i = 0;i<n;i++)
    {
        if(find_parent(i)==i)
        {
           vector<int> q;
           for(int j = 0;j<n;j++) if(j!=i&&find_parent(i)==i) q.pb(j);
           for(int x : q)
           {
               for(int y : q)
               {
                   if(x!=y)
                   {
                       if(p[x][y]!=1) return 0;
                   }
               }
           }
        }
    }
    for(int i = 0;i<n;i++) parent[i] = i, s[i] = 1;
    for(int i = 0;i<n;++i)
        for(int j = 0;j<n;j++)
        if(rr[i]==1&&rr[j]==1&&p[i][j]==2) dsu(i, j);
    for(int i = 0;i<n;++i){
        int x = find_parent(i);
        if(x==i&&rr[i])
        {
            if(s[i]<3) return 0;
            vector<int> q;
            for(int j = 0;j<n;j++)
                if(find_parent(j)==i&&j!=i) q.pb(j);
            q.pb(i);
            int pret = x;
            for(int x : q) res[x][pret] = res[pret][x] = 1, pret = x;
        }
    }
    build(res);
    return 1;
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 10
• Subtask 3: 0 / 19
• Subtask 4: 0 / 35
• Subtask 5: 0 / 21
• Subtask 6: 0 / 4