이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("O2")
#include <bits/stdc++.h>
using namespace std;
typedef int ll;
typedef long long lol;
const ll N = 1e5 + 3, K = 201;
ll par [K][N], n, k, cur, t;
lol dp [2][N], ps [N];
void solve (ll l, ll r, ll optl, ll optr) {
if (l > r) return;
ll m = (l + r) >> 1, till = min(m, optl);
ll bst = -1; lol mx = -1;
for (ll i = m; i >= till; i--) {
lol p = dp[t][i - 1] + ps[i - 1] * (ps[m] - ps[i - 1]);
if (p > mx) mx = p, bst = i;
}
dp[1 - t][m] = mx;
par[cur][m] = bst - 1;
solve(l, m - 1, optl, bst);
solve(m + 1, r, bst, optr);
}
int main ()
{
ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
cin>> n >> k;
for (ll i = 1; i <= n; i++) cin>> ps[i], ps[i] += ps[i - 1];
for (cur = 1, t = 0; cur <= k; cur++, t ^= 1) solve(1, n, 1, n);
cout<< dp[k & 1][n] << '\n';
cur = n;
for (ll i = k; i > 0; --i) cur = par[i][cur], cout<< cur << ' ';
return 0;
}
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