Submission #370756

#TimeUsernameProblemLanguageResultExecution timeMemory
370756fhvirusBigger segments (IZhO19_segments)C++17
100 / 100
94 ms10220 KiB
// Knapsack DP is harder than FFT. #include<bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define ff first #define ss second #define pb emplace_back #define FOR(i,n) for(int i = 0; i < (n); ++i) #define FOO(i,a,b) for(int i = (a); i <= (b); ++i) #define AI(x) (x).begin(),(x).end() template<typename I> bool chmax(I &a, I b){ return a < b ? (a = b, true) : false;} template<typename I> bool chmin(I &a, I b){ return a > b ? (a = b, true) : false;} #ifdef OWO #define debug(args...) LKJ("[ " + string(#args) + " ]", args) void LKJ(){ cerr << endl;} template<typename I, typename...T> void LKJ(I&&x, T&&...t){ cerr<<x<<", ", LKJ(t...);} template<typename I> void DE(I a, I b){ while(a < b) cerr<<*a<<" \n"[next(a)==b], ++a;} #else #define debug(...) 0 #define DE(...) 0 #endif #ifndef OWO #pragma GCC optimize("Ofast") #endif const int N = 5e5 + 225; int n, a[N]; ll s[N]; int32_t main(){ ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0); cin >> n; FOO(i,1,n) cin >> a[i]; FOO(i,1,n) s[i] = s[i-1] + a[i]; vector<int> dp(n + 1, 0); vector<int> mx(n + 1, 0); FOO(i,1,n){ chmax(mx[i], mx[i-1]); dp[i] = dp[mx[i]] + 1; int id = lower_bound(s, s + n + 1, 2 * s[i] - s[mx[i]]) - s; chmax(mx[id], i); } cout << dp[n]; return 0; }
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