제출 #369848

#제출 시각아이디문제언어결과실행 시간메모리
369848wiwihoAliens (IOI16_aliens)C++14
0 / 100
2066 ms388 KiB
#include "aliens.h" #include <bits/stdc++.h> #include <bits/extc++.h> #define StarBurstStream ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); #define iter(a) a.begin(), a.end() #define riter(a) a.rbegin(), a.rend() #define lsort(a) sort(iter(a)) #define gsort(a) sort(riter(a)) #define pb(a) push_back(a) #define eb(a) emplace_back(a) #define pf(a) push_front(a) #define ef(a) emplace_front(a) #define pob pop_back() #define pof pop_front() #define mp(a, b) make_pair(a, b) #define F first #define S second #define mt make_tuple #define gt(t, i) get<i>(t) #define iceil(a, b) (((a) + (b) - 1) / (b)) #define tomax(a, b) ((a) = max((a), (b))) #define tomin(a, b) ((a) = min((a), (b))) #define topos(a) ((a) = (((a) % MOD + MOD) % MOD)) #define uni(a) a.resize(unique(iter(a)) - a.begin()) #define printv(a, b) {bool pvaspace=false; \ for(auto pva : a){ \ if(pvaspace) b << " "; pvaspace=true;\ b << pva;\ }\ b << "\n";} using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef unsigned long long ull; typedef long double ld; using pii = pair<int, int>; using pll = pair<ll, ll>; using pdd = pair<ld, ld>; using tiii = tuple<int, int, int>; const ll MOD = 1000000007; const ll MAX = 2147483647; template<typename A, typename B> ostream& operator<<(ostream& o, pair<A, B> p){ return o << '(' << p.F << ',' << p.S << ')'; } struct Line{ ll a, b, t; Line(ll a = 0, ll b = 1LL << 60, ll t = 0): a(a), b(b), t(t) {} pll operator()(ll x){ return mp(a * x + b, t); } }; struct Node{ Line ln; int l = -1, r = -1; }; int n, m; struct LiChaoTree{ vector<Node> st; int ts = 0; int build(int l = 0, int r = m - 1){ int id = ts++; if(l == r) return id; int mid = (l + r) / 2; st[id].l = build(l, mid); st[id].r = build(mid + 1, r); return id; } void modify(Line ln, int L = 0, int R = m - 1, int id = 0){ int M = (L + R) / 2; // cerr << "modify " << ln(M) << " " << st[id].ln(M) << " " << L << " " << R << "\n"; if(ln(M) <= st[id].ln(M)) swap(ln, st[id].ln); if(L == R) return; if(ln.a <= st[id].ln.a) modify(ln, L, M, st[id].l); else modify(ln, M + 1, R, st[id].r); } pll query(int pos, int L = 0, int R = m - 1, int id = 0){ if(L == R) return st[id].ln(pos); int M = (L + R) / 2; if(pos >= M) return min(st[id].ln(pos), query(pos, L, M, st[id].l)); else return min(st[id].ln(pos), query(pos, M + 1, R, st[id].r)); } }; vector<pll> a; pll operator+(pll a, pll b){ return mp(a.F + b.F, a.S + b.S); } pll calc(ll p){ // cerr << "calc " << p << "\n"; vector<pll> dp(n); LiChaoTree st; st.st.resize(2 * m); st.build(); // cerr << "add " << -2 * a[0].F << " " << a[0].F * a[0].F << " " << 0 << "\n"; st.modify(Line(-2 * a[0].F, a[0].F * a[0].F, 0)); for(int i = 0; i < n; i++){ pll tmp = st.query(a[i].S); // cerr << i << " " << tmp << "\n"; dp[i] = tmp + mp(a[i].S * a[i].S + p, 1); if(i == n - 1) continue; // cerr << "add " << -2 * a[i + 1].F << " " << a[i + 1].F * a[i + 1].F + dp[i].F - max(0LL, a[i].S - a[i + 1].F) * max(0LL, a[i].S - a[i + 1].F) << " " << dp[i].S << "\n"; st.modify(Line(-2 * a[i + 1].F, a[i + 1].F * a[i + 1].F + dp[i].F - max(0LL, a[i].S - a[i + 1].F) * max(0LL, a[i].S - a[i + 1].F), dp[i].S)); } // printv(dp, cerr); return dp[n - 1]; } ll take_photos(int N, int M, int k, vector<int> R, vector<int> C){ n = N; m = M; multiset<int> st; vector<vector<int>> e(m); for(int i = 0; i < n; i++){ if(R[i] <= C[i]){ e[R[i]].eb(MAX); e[C[i]].eb(R[i]); } else{ e[C[i]].eb(MAX); e[R[i]].eb(C[i]); } } for(int i = 0; i < m; i++){ gsort(e[i]); for(int j : e[i]){ if(j == MAX) st.insert(i); else{ st.erase(st.find(j)); if(!st.empty() && *st.begin() <= j) continue; a.eb(mp(j - 1, i)); } } } n = a.size(); // printv(a, cerr); if(calc(0).S <= k){ // cerr << calc(0) << "\n"; return calc(0).F; } ll ans = MAX; for(int i = 0; i <= (ll) m * m; i++){ pll tmp = calc(i); if(tmp.S <= k) ans = min(ans, tmp.F - tmp.S * i); } return ans; // ll l = 0, r = 1LL << 60; // while(l < r){ // ll mid = (l + r) / 2; // if(calc(mid).S <= k) r = mid; // else l = mid + 1; // } //// cerr << l << " " << calc(l) << "\n"; // return calc(l).F - k * l; }
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