제출 #368156

#제출 시각아이디문제언어결과실행 시간메모리
368156Nima_Naderi회문 (APIO14_palindrome)C++14
0 / 100
718 ms63172 KiB
/** Im the best because i work as hard as i possibly can **/ #pragma GCC optimize("O2") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define all(x) (x).begin(),(x).end() #define F first #define S second #define Mp make_pair #define fast_io ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); #define file_io freopen("in.txt" , "r+" , stdin) ; freopen("out.txt" , "w+" , stdout); #define endl "\n" const int N = 3e5 + 10; const ll mod = 884577481; const ll mod2 = 998244353; const ll inf = 8e18; const int LOG = 20; const ll base = 609859; string s; char C[N]; ll PW, n, T, lcp[N], tmp[N], Cnt[N], SA[N], rnk[LOG][N], seg[N << 2]; ll pw[N], hshL[N], hshR[N]; inline bool CMP(int i, int j){ if(rnk[PW - 1][i] != rnk[PW - 1][j]) return (rnk[PW - 1][i] < rnk[PW - 1][j]); i += (1LL << (PW - 1)), j += (1LL << (PW - 1)); if(i > n || j > n) return (i > j); return (rnk[PW - 1][i] < rnk[PW - 1][j]); } inline void BuildSuffixArray(const string &s){ assert((s[0] == '$') && (n + 1 == (int)s.size())); iota(SA + 1, SA + n + 1, 1), SA[0] = n + 1; for(int i = 1; i <= n; i ++) rnk[0][i] = s[i]; for(PW = 1; PW < LOG; PW ++){ sort(SA + 1, SA + n + 1, CMP); for(int i = 2; i <= n; i ++){ tmp[i] = tmp[i - 1] + CMP(SA[i - 1], SA[i]); } for(int i = 1; i <= n; i ++){ rnk[PW][SA[i]] = tmp[i]; } } //! tmp is 0-indexed } inline void BuildLcpTable(const string &s){ assert((s[0] == '$') && (n + 1 == (int)s.size())); for(int i = 1, k = 0; i <= n; i ++){ if(rnk[LOG - 1][i] == n - 1) continue; if(k) k --; while(s[i + k] == s[SA[rnk[LOG - 1][i] + 2] + k]){ k ++; } lcp[rnk[LOG - 1][i] + 2] = k; } } inline ll baze(int l, int r) { return (hshL[r] - (hshL[l - 1] * pw[r - l + 1] % mod) + mod) % mod; } inline ll baze2(int l, int r) { return (hshR[l] - (hshR[r + 1] * pw[r - l + 1] % mod) + mod) % mod; } void build(int v = 1, int tl = 1, int tr = n) { if(tl == tr) { seg[v] = lcp[tl]; return; } int mid = (tl + tr) >> 1; build(v << 1, tl, mid), build(v << 1 | 1, mid + 1, tr); seg[v] = min(seg[v << 1], seg[v << 1 | 1]); } int find_nxt(int p, int x, int v = 1, int tl = 1, int tr = n) { if(p > n) return n + 1; if(tr < p) return -1; if(seg[v] >= x) { if(tr == n) return n + 1; return -1; } if(tl == tr) return tl; int mid = (tl + tr) >> 1; int cu = find_nxt(p, x, v << 1, tl, mid); if(cu == -1) cu = find_nxt(p, x, v << 1 | 1, mid + 1, tr); return cu; } int find_prv(int p, int x, int v = 1, int tl = 1, int tr = n) { if(tl > p) return -1; if(seg[v] >= x) { if(tl == 1) return 0; return -1; } if(tl == tr) return tl; int mid = (tl + tr) >> 1; int cu = find_prv(p, x, v << 1 | 1, mid + 1, tr); if(cu == -1) cu = find_prv(p, x, v << 1, tl, mid); return cu; } ll calc(int l, int r) { int sz = r - l + 1, id = rnk[PW - 1][l]; int L = find_prv(id, sz); int R = find_nxt(id + 1, sz); return R - L; } int main() { scanf("%s", C); n = strlen(C); s = C; s = "$" + s; BuildSuffixArray(s); BuildLcpTable(s); build(); ll tot = 0; for(ll i = 1; i <= n; i ++) { int d = 0, up = min(i - 1, n - i) + 1; while(up - d > 1) { int mid = (up + d) >> 1; if(baze(i, i + mid) == baze2(i - mid, i)) d = mid; else up = mid; } tot = max(tot, calc(i - d, i + d) * (2 * d + 1)); } for(ll i = 1; i < n; i ++) { if(s[i] != s[i + 1]) continue; int d = 0, up = min(i - 1, n - i - 1) + 1; while(up - d > 1) { int mid = (up + d) >> 1; if(baze(i + 1, i + 1 + mid) == baze2(i - mid, i)) d = mid; else up = mid; } tot = max(tot, calc(i - d, i + d + 1) * (2 * d + 2)); } printf("%lld", tot); return 0; }

컴파일 시 표준 에러 (stderr) 메시지

palindrome.cpp: In function 'int main()':
palindrome.cpp:130:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  130 |     scanf("%s", C);
      |     ~~~~~^~~~~~~~~
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