제출 #368103

#제출 시각아이디문제언어결과실행 시간메모리
368103Akashi모임들 (IOI18_meetings)C++14
41 / 100
334 ms135720 KiB
#include <bits/stdc++.h> #include "meetings.h" using namespace std; const int DIM = 750005; const long long INF = 1e18; int n; int val[DIM]; struct Line { long long a, b; Line(long long _a = 0, long long _b = 0) {a = _a; b = _b;} long long get(int t) { return 1LL * a * t + b; } }; struct SegTree { long long lazy[4 * DIM]; Line line[4 * DIM]; void build(int st = 1, int dr = n, int nod = 1) { lazy[nod] = 0; line[nod] = {0, INF}; if (st == dr) {line[nod] = {0, 0}; return ;} build(st, (st + dr) / 2, nod * 2); build((st + dr) / 2 + 1, dr, nod * 2 + 1); } void upd(int nod, int val) { lazy[nod] += val; line[nod].b += val; } void propag(int nod) { if (lazy[nod] == 0) return ; for (int i = nod * 2; i <= nod * 2 + 1 ; ++i) upd(i, lazy[nod]); lazy[nod] = 0; } long long query(int x, int st = 1, int dr = n, int nod = 1) { if (st == dr) return line[nod].get(x); propag(nod); int mij = (st + dr) / 2; if (x <= mij) return min(line[nod].get(x), query(x, st, mij, nod * 2)); return min(line[nod].get(x), query(x, mij + 1, dr, nod * 2 + 1)); } void update(int x, int y, long long val, int st = 1, int dr = n, int nod = 1) { if (x <= st && dr <= y) {upd(nod, val); return ;} propag(nod); int mij = (st + dr) / 2; if (x <= mij) update(x, y, val, st, mij, nod * 2); if (mij + 1 <= y) update(x, y, val, mij + 1, dr, nod * 2 + 1); } void idk(int l, int r, Line newLine, int st = 1, int dr = n, int nod = 1) { if (l <= st && dr <= r) { long long A = newLine.get(st), B = line[nod].get(st), C = newLine.get(dr), D = line[nod].get(dr); if (A <= B && C <= D) {line[nod] = newLine; return ;} if (A >= B && C >= D) return ; propag(nod); int mij = (st + dr) / 2; if (A <= B) swap(line[nod], newLine); if (line[nod].get(mij) <= newLine.get(mij)) idk(l, r, newLine, mij + 1, dr, nod * 2 + 1); else swap(line[nod], newLine), idk(l, r, newLine, st, mij, nod * 2); return ; } propag(nod); int mij = (st + dr) / 2; if (l <= mij) idk(l, r, newLine, st, mij, nod * 2); if (mij + 1 <= r) idk(l, r, newLine, mij + 1, dr, nod * 2 + 1); } void merge(int l, int split, int r, int tip) { if (tip == 0) { long long aux = query(split - 1); Line newLine = {val[split], aux - 1LL * (split - 1) * val[split]}; idk(split, r, newLine); } else { long long aux = query(split + 1); Line newLine = {-val[split], aux + 1LL * (split + 1) * val[split]}; idk(l, split, newLine); } } }; SegTree L, R; struct query { int l, r, ind; }; vector <long long> ans; vector <query> myQ[DIM]; pair <int, int> arb[4 * DIM]; pair <int, int> max(pair <int, int> a, pair <int, int> b) { if (a.first > b.first || (a.first == b.first && a.second < b.second)) return a; return b; } void build_max(int st = 1, int dr = n, int nod = 1) { if (st == dr) {arb[nod] = {val[st], st}; return ;} int mij = (st + dr) / 2; build_max(st, mij, nod * 2); build_max(mij + 1, dr, nod * 2 + 1); arb[nod] = max(arb[nod * 2], arb[nod * 2 + 1]); } pair <int, int> _get_max(int x, int y, int st = 1, int dr = n, int nod = 1) { if (x <= st && dr <= y) return arb[nod]; pair <int, int> ans = {-1, -1}; int mij = (st + dr) / 2; if (x <= mij) ans = max(ans, _get_max(x, y, st, mij, nod * 2)); if (mij + 1 <= y) ans = max(ans, _get_max(x, y, mij + 1, dr, nod * 2 + 1)); return ans; } int get_max(int x, int y) { return _get_max(x, y).second; } void solve(int l, int r) { if (l > r) return ; int split = get_max(l, r); solve(l, split - 1); solve(split + 1, r); for (auto it : myQ[split]) ans[it.ind] = min(L.query(it.r) + 1LL * (split - it.l + 1) * val[split], R.query(it.l) + 1LL * (it.r - split + 1) * val[split]); L.update(split, r, 1LL * val[split] * (split - l + 1)); if (split != l) L.merge(l, split, r, 0); R.update(l, split, 1LL * val[split] * (r - split + 1)); if (split != r) R.merge(l, split, r, 1); } std::vector<long long> minimum_costs(std::vector<int> H, std::vector<int> LQ, std::vector<int> RQ) { n = (int)H.size(); for (int i = 1; i <= n ; ++i) val[i] = H[i - 1]; build_max(); int Q = (int)LQ.size(); ans.resize(Q); for (int i = 0; i < Q ; ++i) myQ[get_max(LQ[i] + 1, RQ[i] + 1)].push_back({LQ[i] + 1, RQ[i] + 1, i}); L.build(); R.build(); solve(1, n); return ans; }
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