Submission #367811

#	Time	Username	Problem	Language	Result	Execution time	Memory
367811		vaaven	Semiexpress (JOI17_semiexpress)	C++14	100 / 100	15 ms	4580 KiB

semiexpress

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#include <iostream>
#include <vector>
#include <algorithm>
#include <math.h>
#include <set>
#include <stack>
#include <iomanip>
#include <bitset>
#include <map>
#include <cassert>
#include <array>
#include <queue>
#include <cstring>
#include <random>
#include <unordered_set>
#include <unordered_map>
#define pqueue priority_queue
#define pb(x) push_back(x)
 #define endl '\n'
#define all(x) x.begin(), x.end()
#define int long  long
    
using namespace std;
    
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef vector<int> vi;
typedef vector<vector<int> > vvi;
// typedef tuple<ll, ll, ll> tiii;
typedef pair<int, int> pii;
typedef vector<pair<int, int> > vpii;
typedef vector<bool> vb;
typedef vector<string> vs;
typedef vector<char> vc;
    
const int inf = 1e9 + 228;
const int infll = 1e18;
const ll mod = 1e9 + 7;
const ll mod2 = 998244353;
const ld eps = 1e-14;
    
    
void fast_io(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);
//    freopen("inputik.txt", "r", stdin);
//    freopen("outputik.txt", "w", stdout);
}
 
   
void solve(){
    int n, m, k;
    cin >> n >> m >> k;
    k -= m;
    int a, b, c;
    cin >> a >> b >> c;
    int t;
    cin >> t;
    vi s(m);
    for(int &i:s)
        cin >> i;
    vi kek;
    int ans = 0;
    if((n-1) * b <= t)
        ans++;
    for(int i=0; i+1<m; i++){
        int time = (s[i]-1) * b;
        if(time > t)
            break;
        int can = (t - time)/a;
//        cout << can << endl;
        can = min(can, s[i+1]-s[i]-1);
        ans += can+1 - (i == 0);
        int cur = s[i] + can + 1;
        for(int j=0; j<k && cur < s[i+1]; j++){
            time = (s[i]-1) * b + (cur-s[i]) * c;
            if(time > t)
                break;
            can = (t - time)/a;
            can = min(can, s[i+1]-cur-1);
            kek.pb(can+1);
            cur += can+1;
        }
    }
    sort(all(kek));
    reverse(all(kek));
    for(int i=0; i<min(k, (int)kek.size()); i++)
        ans += kek[i];
    cout << ans << endl;
       
}
   
signed main(){
     fast_io();
//  ;(time(NULL));
    cout << fixed << setprecision(10);
    int q = 1;
//    cin >> q;
    while(q--)
        solve();
}

• Subtask 1: 18 / 18
• Subtask 2: 30 / 30
• Subtask 3: 52 / 52