#include<bits/stdc++.h>
#pragma GCC optimize("unroll-loops,no-stack-protector,Ofast")
using namespace std;
typedef int ll;
typedef long double ld;
typedef pair<ll,ll> pll;
const ll MOD=1e9+7;
const ll MOD2=998244353;
const ll N=1e5+5;
const ld pi=acos(-1);
//const ll INF=(1LL<<60);
const ll B=1500;
#define SQ(i) ((i)*(i))
#define REP(i,n) for(ll i=0;i<n;i++)
#define REP1(i,n) for(ll i=1;i<=n;i++)
#define pb push_back
#define mp make_pair
#define X first
#define Y second
#define setp setprecision
#define lwb lower_bound
#define SZ(_a) (ll)_a.size()
struct edge{
ll x,y,c;
}ed[N];
vector<ll> query,changed,join[N],unchanged;
ll n,m,q,ty[N],id[N],w[N],ans[N],vis[N];
ll dir[N],sz[N],stk[N],now;
inline ll f(ll idx){
while(idx!=dir[idx])idx=dir[idx];
return idx;
}
inline void uni(ll a,ll b){
a=f(a);b=f(b);
if(sz[a]>sz[b])swap(a,b);
if(a==b){
stk[++now]=0;
}else{
stk[++now]=a;
dir[a]=b;
sz[b]+=sz[a];
}
}
inline void undo(){
if(stk[now]==0){
--now;
}else{
ll a=stk[now];
sz[dir[a]]-=sz[a];
dir[a]=a;
--now;
}
}
int main(){
ios_base::sync_with_stdio(0);cin.tie(0);
cin>>n>>m;
REP1(i,m)cin>>ed[i].x>>ed[i].y>>ed[i].c;
cin>>q;
REP1(i,q)cin>>ty[i]>>id[i]>>w[i];
for(int i=1;i<=q;i+=B){
//reset
unchanged.clear();
changed.clear();
query.clear();
memset(vis,0,sizeof(vis));
REP1(j,n)dir[j]=j,sz[j]=1;
//
ll ql=i,qr=min(i+B,q+1)-1;
for(int j=ql;j<=qr;++j){
if(ty[j]==1){
vis[id[j]]=1;
changed.pb(id[j]);
}else{
query.pb(j);
}
}
REP1(j,m)if(!vis[j])unchanged.pb(j);
for(int j=ql;j<=qr;j++){
if(ty[j]==1){
ed[id[j]].c=w[j];
}else{
for(auto ii:changed){
if(ed[ii].c>=w[j])join[j].pb(ii);
}
}
}
//sort
sort(unchanged.begin(),unchanged.end(),[&](ll a,ll b){
return (ed[a].c>ed[b].c);
});
sort(query.begin(),query.end(),[&](ll a,ll b){
return w[a]>w[b];
});
//
//
//cout<<"query\n";
ll pos=0;
for(auto j:query){
//cout<<ty[j]<<" "<<id[j]<<" "<<w[j]<<"\n";
while(pos<SZ(unchanged)&&ed[unchanged[pos]].c>=w[j])uni(ed[unchanged[pos]].x,ed[unchanged[pos]].y),++pos;
ll ti=0;
for(auto ii:join[j])++ti,uni(ed[ii].x,ed[ii].y);
ans[j]=sz[f(id[j])];
while(ti)undo(),ti--;
}
//change
}
REP1(i,q)if(ty[i]==2)cout<<ans[i]<<"\n";
return 0;
}
