Submission #366539

#	Time	Username	Problem	Language	Result	Execution time	Memory
366539		ne4eHbKa	3D Histogram (COCI20_histogram)	C++17	20 / 110	2572 ms	1740 KiB

histogram

#include <bits/stdc++.h>
using namespace std;
#ifndef _LOCAL
//#pragma GCC optimize("O3,Ofast")
#else
#pragma GCC optimize("O0")
#endif
template<typename t> inline void umin(t &a, const t b) {a = min(a, b);}
template<typename t> inline void umax(t &a, const t b) {a = max(a, b);}
typedef pair<int, int> pii;
typedef long long ll;
typedef long double ld;
ll time() {return chrono::system_clock().now().time_since_epoch().count();}
mt19937 rnd(time());
#define ft first
#define sd second
#define len(f) int((f).size())
#define bnd(f) (f).begin(), (f).end()
#define _ <<' '<<
const int inf = 1e9 + 5;
const ll inf64 = 4e18 + 5;
const int md = 998244353;
namespace MD {
    void add(int &a, const int b) {if((a += b) >= md) a -= md;}
    void sub(int &a, const int b) {if((a -= b) < 0) a += md;}
    int prod(const int a, const int b) {return ll(a) * b % md;}
};

void solve() {
    int n; cin >> n;
    int a[n], b[n];
    for(int i =0; i < n; ++i) cin >> a[i] >> b[i];
    ll ans = 0;
    for(int i = 0; i < n; ++i) {
        ll f = a[i], t = b[i];
        umax(ans, f * t);
        for(int j = i + 1; j < n; ++j) {
            umin<ll>(f, a[j]);
            umin<ll>(t, b[j]);
            umax(ans, (j - i + 1) * f * t);
        }
    }
    cout << ans << endl;
}

int main() {
    ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#ifndef _LOCAL_
//    freopen("file.in", "r", stdin);
//    freopen("file.out", "w", stdout);
#else
    system("color a");
    freopen("in.txt", "r", stdin);
    int t; cin >> t;
    while(t--)
#endif
    solve();
}

• Subtask 1: 20 / 20
• Subtask 2: 0 / 90