제출 #365443

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
365443		ACmachine	송금 (JOI19_remittance)	C++17	0 / 100	1 ms	364 KiB

remittance

#include <bits/stdc++.h>
using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;

template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename T, typename U> using ordered_map = tree<T, U, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

typedef long long ll;
typedef long double ld;
typedef double db;
typedef string str;

typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<pii> vpii;
typedef vector<pll> vpll;
typedef vector<str> vstr;

#define FOR(i,j,k,in) for(int i=(j); i < (k);i+=in)
#define FORD(i,j,k,in) for(int i=(j); i >=(k);i-=in)
#define REP(i,b) FOR(i,0,b,1)
#define REPD(i,b) FORD(i,b,0,1)
#define pb push_back 
#define mp make_pair
#define ff first
#define ss second
#define all(x) begin(x), end(x)
#define rsz resize 
#define MANY_TESTS int tcase; cin >> tcase; while(tcase--)
	
const double EPS = 1e-9;
const int MOD = 1e9+7; // 998244353;
const ll INFF = 1e18;
const int INF = 1e9;
const ld PI = acos((ld)-1);
const vi dy = {1, 0, -1, 0, -1, 1, 1, -1};
const vi dx = {0, 1, 0, -1, -1, 1, -1, 1};

#ifdef DEBUG
#define DBG if(1)
#else
#define DBG if(0)
#endif

#define dbg(x) cout << "(" << #x << " : " << x << ")" << endl;
// ostreams
template <class T, class U>
ostream& operator<<(ostream& out, const pair<T, U> &par) {out << "[" << par.first << ";" << par.second << "]"; return out;}
template <class T>
ostream& operator<<(ostream& out, const set<T> &cont) { out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; }
template <class T, class U>
ostream& operator<<(ostream& out, const map<T, U> &cont) {out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; }
template<class T>
ostream& operator<<(ostream& out, const vector<T> &v){ out << "[";  REP(i, v.size()) out << v[i] << ", ";  out << "]"; return out;}
// istreams
template<class T>
istream& operator>>(istream& in, vector<T> &v){ for(auto &x : v) in >> x; return in; }
template<class T, class U>
istream& operator>>(istream& in, pair<T, U> &p){ in >> p.ff >> p.ss; return in; }
//searches
template<typename T, typename U>
T bsl(T lo, T hi, U f){ hi++; T mid; while(lo < hi){ mid = (lo + hi)/2; f(mid) ? hi = mid : lo = mid+1; } return lo; }
template<typename U>
double bsld(double lo, double hi, U f, double p = 1e-9){ int r = 3 + (int)log2((hi - lo)/p); double mid; while(r--){ mid = (lo + hi)/2; f(mid) ? hi = mid : lo = mid; } return (lo + hi)/2; }
template<typename T, typename U>
T bsh(T lo, T hi, U f){ lo--; T mid; while(lo < hi){ mid = (lo + hi + 1)/2; f(mid) ? lo = mid : hi = mid-1; } return lo; }
template<typename U>
double bshd(double lo, double hi, U f, double p = 1e-9){ int r = 3+(int)log2((hi - lo)/p); double mid; while(r--){ mid = (lo + hi)/2; f(mid) ? lo = mid : hi = mid; } return (lo + hi)/2; }
// some more utility functions
template<typename T>
pair<T, int> get_min(vector<T> &v){ typename vector<T> :: iterator it = min_element(v.begin(), v.end()); return mp(*it, it - v.begin());}
template<typename T>
pair<T, int> get_max(vector<T> &v){ typename vector<T> :: iterator it = max_element(v.begin(), v.end()); return mp(*it, it - v.begin());}        
template<typename T> bool ckmin(T& a, const T& b){return b < a ? a = b , true : false;}
template<typename T> bool ckmax(T& a, const T& b){return b > a ? a = b, true : false;}
struct node{
    int val = -INF; int ind; 
    void apply(int v){
        val += v;
    }
};
struct segtree{
    node comb(node const &a, node const &b){
        node res;
        res.val = max(a.val, b.val);
        if(a.val > b.val) res.ind = a.ind;
        else res.ind = b.ind;
        return res;
    }
    int n;
    vector<node> tree;
    segtree(int _n){
        n = 1;
        while(n < _n) n*= 2;
        tree.resize(2*n);
    }
    void build(vector<node> &init){
        REP(i, n){
            if(i < init.size()) 
                tree[i + n] = init[i];
        }
        FORD(i, n - 1, 1, 1) 
            tree[i] = comb(tree[i << 1], tree[i << 1 | 1]);
    }
    void upd(int pos, ll val){
        pos += n;
        tree[pos].apply(val);
        for(int i = pos / 2; i > 0; i/= 2) 
            tree[i] = comb(tree[i << 1], tree[i << 1 | 1]);
    }
    node query(int l, int r){ return query0(l, r, 0, n, 1); }
    node query0(int l, int r, int beg, int end, int v){
        if(beg >= l && end <= r)
            return tree[v];
        int mid = (beg + end) >> 1;
        node res;
        if(mid <= l || beg >= r) res = query0(l, r, mid, end, v<<1|1);
        else if(end <= l || mid >= r) res = query0(l, r, beg, mid, v<<1);
        else res = comb(query0(l, r, beg, mid, v << 1), query0(l, r, mid, end, v<<1|1));
        return res;
    }
};

    
int main(){
 	ios_base::sync_with_stdio(false);
 	cin.tie(NULL); cout.tie(NULL);
	int n; cin >> n;
    vll a(n), b(n);
    REP(i, n) cin >> a[i] >> b[i];
    vector<node> init(n);
    REP(i, n){
        init[i].val = a[i] - b[i];
        init[i].ind = i;
    }
    segtree st(n);
    st.build(init);
    while(true){
        auto no = st.query(0, st.n);
        if(no.val <= 1) break;
        st.upd(no.ind, -no.val/2 * 2);
        a[no.ind] -= no.val / 2 * 2;
        int nxt= no.ind + 1;
        if(nxt >= n) nxt-=n;
        a[nxt] += no.val / 2;
        st.upd(nxt, no.val/2);  
    }
    bool can = true;
    REP(i, n){
        if(a[i] != b[i]) can = false;
    }
    if(can){
        cout << "Yes" << "\n";
    }
    else{
        cout << "No" << "\n";
    }
	
    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

remittance.cpp: In member function 'void segtree::build(std::vector<node>&)':
remittance.cpp:106:18: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<node>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  106 |             if(i < init.size())
      |                ~~^~~~~~~~~~~~~

• Subtask 1: 0 / 15
• Subtask 2: 0 / 40
• Subtask 3: 0 / 45