Submission #362590

#TimeUsernameProblemLanguageResultExecution timeMemory
362590idk321Jousting tournament (IOI12_tournament)C++11
100 / 100
123 ms16640 KiB
#include <bits/stdc++.h> using namespace std; const int N = 100000; int tree[4 * N]; int rmq[N][20]; array<int, 2> best[N]; list<int>::iterator to[N]; list<int> l; int* rnk; int n; void cons() { for (int i = 0; i < n - 1; i++) { rmq[i][0] = rnk[i]; } for (int j = 1; j < 20; j++) { for (int i = 0; i + (1 << j) - 1 < n - 1; i++) { rmq[i][j] = max(rmq[i][j - 1], rmq[i + (1 << (j - 1))][j - 1]); } } } int getMax(int from, int to) { for (int i = 19; i >= 0; i--) { if (from + (1 << i) - 1 <= to) { return max(rmq[from][i], rmq[to - (1 << i) + 1][i]); } } return -1; } void make(int num, int i, int a, int b, int node) { if (a == b) { tree[node] = num; return; } int mid =(a + b) / 2; if (i <= mid) make(num, i, a, mid, node * 2); if (i > mid) make(num, i, mid + 1, b, node * 2 + 1); tree[node] = tree[node * 2] + tree[node * 2 + 1]; } int kth(int k, int a, int b, int node) { if (a == b) { if (k == 0) return a; else return n; } int mid = (a + b) / 2; if (tree[node * 2] > k) return kth(k, a, mid, node * 2); return kth(k - tree[node * 2], mid + 1, b, node * 2 + 1); } int GetBestPosition(int xd, int c, int r, int *K, int *s, int *e) { n = xd; rnk = K; for (int i = 0; i < n; i++) { l.push_back(i); best[i] = {i, 0}; make(1, i, 0, n - 1, 1); } int i = 0; auto it = l.begin(); while (i < n) { to[i] = it; i++; it++; } cons(); for (int i = 0; i < c; i++) { int a = s[i]; int b = e[i]; int x = kth(a, 0, n - 1, 1); int y = kth(b + 1, 0, n - 1, 1) - 1; int cur = getMax(x, y - 1); auto it = to[x]; auto cbest = best[x]; //cout << x << " " << y << endl; it++; while(it != l.end() && *it <= y) { if (best[*it][1] > cbest[1]) { cbest = best[*it]; } make(0, *it, 0, n - 1, 1); it = l.erase(it); } if (cur < r)cbest[1]++; best[x] = cbest; } auto res = best[0]; for (int i = 1; i < n; i++) { if (best[i][1] > res[1]) res = best[i]; } //cout << res[1] << endl; return res[0]; } /* 5 3 3 1 0 2 4 1 3 0 1 0 1 */
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