# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
362434 | ray5273 | Treasure (different grader from official contest) (CEOI13_treasure2) | C++14 | 1 ms | 512 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "treasure.h"
#include <iostream>
using namespace std;
// bool arr[101][101];
// 체크대신에 그냥 바로 Report하면되네
//1+N*N-S의 에너지 사용을 N^2 + 7/16*N^4 이하로 사용하게 하여라
int arr[101][101];
void check_treasure(int N){
int mid = N/2;
//홀짝은 이해해보기
for(int i=mid+1;i<=N;i++)
for(int j=mid+1;j<=N;j++)
arr[i][j] = countTreasure(1,1,i,j);
for(int i=1;i<=mid;i++)
for(int j=mid+1;j<=N;j++)
arr[i][j] = arr[N][j] - countTreasure(i+1,1,N,j); //1,1, to i,j까지 합
for(int i=mid+1;i<=N;i++)
for(int j=1;j<=mid;j++)
arr[i][j] = arr[i][N] - countTreasure(1,j+1,i,N); //1,1 to i,j의 합
for(int i=1;i<=mid;i++)
for(int j=1;j<=mid;j++)
arr[i][j] = arr[i][N] + arr[N][j] + countTreasure(i+1,j+1,N,N) - arr[N][N];//그려보면 이해가능
for(int i=1;i<=N;i++)
for(int j=1;j<=N;j++)
if(arr[i][j]-arr[i-1][j]-arr[i][j-1]+arr[i-1][j-1])
Report(i,j);
}
void findTreasure (int N) {
// int cnt = countTreasure(1, 1, N, N);
// find_treasure(1,1,N,N);
check_treasure(N);
}
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
Fetching results... |