Submission #36210

#	Time	Username	Problem	Language	Result	Execution time	Memory
36210		WhipppedCream	Price List (POI13_cen)	C++14	0 / 100	139 ms	9380 KiB

cen

#include <bits/stdc++.h>
//#ifdef atom #else #endif
using namespace std;
typedef long long ll;
typedef pair<int, int> ii;
#define X first
#define Y second
#define vi vector<int>
#define vvi vector< vi >
#define vii vector< ii >
#define mp make_pair
#define pb push_back
const int maxn = 1e5+5;
int n, m, k, a, b;
vector<int> adj[maxn];
ll odd[maxn];
ll eve[maxn];
ll cost(int x)
{
    return 1LL*min(2*a, b)*(x/2)+a*(x%2);
}
int main()
{
    //#ifndef atom
    //freopen(".in", "r", stdin);
    //freopen(".out", "w", stdout);
    //#endif
    scanf("%d %d %d %d %d", &n, &m, &k, &a, &b);
    for(int i = 1; i<= n; i++) odd[i] = eve[i] = 1e18;
    for(int i = 1; i<= m; i++)
    {
        int a, b; scanf("%d %d", &a, &b);
        adj[a].pb(b); adj[b].pb(a);
    }
    eve[k] = 0;
    queue<ii> Q; Q.push(ii(k, 0));
    while(!Q.empty())
    {
        int u = Q.front().X; int par = Q.front().Y; Q.pop();
        for(auto v : adj[u])
        {
            if(par)
            {
                if(eve[v]> odd[u]+1)
                {
                    eve[v] = odd[u]+1;
                    Q.push(ii(v, 0));
                }
            }
            else
            {
                if(odd[v]> eve[u]+1)
                {
                    odd[v] = eve[u]+1;
                    Q.push(ii(v, 1));
                }
            }
        }
    }
    for(int i = 1; i<= n; i++) printf("%lld\n", min(cost(odd[i]), cost(eve[i])));
}

Compilation message (stderr)

cen.cpp: In function 'int main()':
cen.cpp:28:48: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d %d %d %d", &n, &m, &k, &a, &b);
                                                ^
cen.cpp:32:41: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         int a, b; scanf("%d %d", &a, &b);
                                         ^

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10