Submission #361752

#	Time	Username	Problem	Language	Result	Execution time	Memory
361752		ryansee	기지국 (IOI20_stations)	C++14	0 / 100	5 ms	1376 KiB

stations

#include "stations.h"

#include "bits/stdc++.h"
using namespace std;

#define FAST ios_base::sync_with_stdio(false); cin.tie(0);
#define pb push_back
#define eb emplace_back
#define ins insert
#define f first
#define s second
#define cbr cerr<<"hi\n"
#define mmst(x, v) memset((x), v, sizeof ((x)))
#define siz(x) ll(x.size())
#define all(x) (x).begin(), (x).end()
#define lbd(x,y) (lower_bound(all(x),y)-x.begin())
#define ubd(x,y) (upper_bound(all(x),y)-x.begin())
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
inline long long rand(long long x, long long y) { return rng() % (y+1-x) + x; } //inclusive
string inline to_string(char c) {string s(1,c);return s;} template<typename T> inline T gcd(T a,T b){ return a==0?llabs(b):gcd(b%a,a); }

using ll=long long; 
using ld=long double;
#define FOR(i,s,e) for(ll i=s;i<=ll(e);++i)
#define DEC(i,s,e) for(ll i=s;i>=ll(e);--i)
using pi=pair<ll,ll>; using spi=pair<ll,pi>; using dpi=pair<pi,pi>; 

long long LLINF = 1e18;
int INF = 1e9+1e6;
#define MAXN (200006)

vector<int> label(int n, int k, vector<int> U, vector<int> V) {
	vector<vector<int>> v(n, vector<int>());
	FOR(i,0,n-2) v[U[i]].eb(V[i]), v[V[i]].eb(U[i]);
	vector<int> C(n, 0);
	ll bruh = 0;
	ll co=0, even=2000, odd = 2001;
	function<void(int,int)>dfs=[&](int x,int p){
		int c = 0;
		for(auto i:v[x]) if(i^p) ++ c;
		if(bruh) {
			C[x] = bruh == 1 ? even : odd;
			if(bruh == 1) even += 2; else odd += 2;
			for(auto i:v[x]) if(i^p) dfs(i, x);
		} else if(c == 1) {
			C[x] = co ++;
			for(auto i:v[x]) if(i^p) dfs(i, x);
		} else {
			C[x] = co ++;
			for(auto i:v[x]) if(i^p) {
				++ bruh;
				dfs(i, x);
			}
		}
	};
	FOR(i,0,n-1) if(siz(v[i]) == 1) { dfs(i, i); break; }
	return C;
}

int find_next_station(int s, int t, vector<int> c) {
	if(s > t) {
		return *min_element(all(c));
	} else {
		if(s < 2000 && siz(c) == 2) return *max_element(all(c));
		if(s >= 2000 && t >= 2000 && (s&1) != (t&1)) {
			return *min_element(all(c));
		}
		if(s >= 2000 && t >= 2000 && (s&1) == (t&1)) {
			return *max_element(all(c));
		}
		assert(s < 2000 && siz(c) == 3);
		for(auto i:c) if(i >= 2000 && (i&1) == (t&1)) {
			return i;
		}
		return c[0];
	}
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 8
• Subtask 3: 0 / 16
• Subtask 4: 0 / 10
• Subtask 5: 0 / 61