이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#define taskname "test"
#include <bits/stdc++.h>
using namespace std;
#define sz(x) (int)x.size()
#define fi first
#define se second
typedef long long lli;
typedef pair<int, int> pii;
const int maxn = 3e5 + 5;
const lli inf = 1e18;
int n, m;
int a[maxn], b[maxn], c[maxn], d[maxn];
vector<int> vals;
struct segment_tree
{
    lli min_val[maxn * 4];
    segment_tree()
    {
        fill(begin(min_val), end(min_val), inf);
    }
    void update(int x, int l, int r, int p, lli k)
    {
        if(l == r)
        {
            min_val[x] = min(min_val[x], k);
            return;
        }
        int mid = (l + r) / 2;
        if(p <= mid) update(x * 2, l, mid, p, k);
        else update(x * 2 + 1, mid + 1, r, p, k);
        min_val[x] = min(min_val[x * 2], min_val[x * 2 + 1]);
    }
    lli get(int x, int l, int r, int L, int R)
    {
        if(L > r || l > R) return inf;
        if(l >= L && r <= R)
            return min_val[x];
        int mid = (l + r) / 2;
        return min(get(x * 2, l, mid, L, R),
                   get(x * 2 + 1, mid + 1, r, L, R));
    }
};
segment_tree tree_f, tree_g;
void read_input()
{
    cin >> n >> m;
    for(int i = 1; i <= n; ++i)
        cin >> a[i] >> b[i] >> c[i] >> d[i];
}
int lwb(const vector<int>&arr, int k)
{
    return lower_bound(arr.begin(), arr.end(), k) - arr.begin() + 1;
}
void init()
{
    vals.push_back(1);
    vals.push_back(m);
    for(int i = 1; i <= n; ++i)
    {
        vals.push_back(a[i]);
        vals.push_back(b[i]);
        vals.push_back(c[i]);
    }
    sort(vals.begin(), vals.end());
    vals.erase(unique(vals.begin(), vals.end()), vals.end());
    m = sz(vals);
    for(int i = 1; i <= n; ++i)
    {
        a[i] = lwb(vals, a[i]);
        b[i] = lwb(vals, b[i]);
        c[i] = lwb(vals, c[i]);
    }
}
void solve()
{
    tree_f.update(1, 1, m, 1, 0);
    tree_g.update(1, 1, m, m, 0);
    lli ans = inf;
    for(int i = 1; i <= n; ++i)
    {
        ans = min(ans, tree_f.get(1, 1, m, a[i], b[i]) + tree_g.get(1, 1, m, a[i], b[i]) + d[i]);
        lli k = tree_f.get(1, 1, m, a[i], b[i]) + d[i];
        tree_f.update(1, 1, m, c[i], k);
        k = tree_g.get(1, 1, m, a[i], b[i]) + d[i];
        tree_g.update(1, 1, m, c[i], k);
    }
    if(ans == inf) ans = -1;
    cout << ans << '\n';
}
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    read_input();
    init();
    solve();
}
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