제출 #361288

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
361288		AmShZ	철인 이종 경기 (APIO18_duathlon)	C++11	23 / 100	141 ms	24172 KiB

count_triplets

//khodaya khodet komak kon
# include <bits/stdc++.h>
 
/*
// ordered_set 
# include <ext/pb_ds/assoc_container.hpp>
# include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
# define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update> 
*/
 
using namespace std;
 
typedef long long                                        ll;
typedef long double                                      ld;
typedef pair <int, int>                                  pii;
typedef pair <pii, int>                                  ppi;
typedef pair <int, pii>                                  pip;
typedef pair <pii, pii>                                  ppp;
typedef pair <ll, ll>                                    pll;
 
# define A                                               first
# define B                                               second
# define endl                                            '\n'
# define sep                                             ' '
# define all(x)                                          x.begin(), x.end()
# define kill(x)                                         return cout << x << endl, 0
# define SZ(x)                                           int(x.size())
# define lc                                              id << 1
# define rc                                              id << 1 | 1
# define InTheNameOfGod                                  ios::sync_with_stdio(0);cin.tie(0); cout.tie(0);
 
ll power(ll a, ll b, ll md) {return (!b ? 1 : (b & 1 ? a * power(a * a % md, b / 2, md) % md : power(a * a % md, b / 2, md) % md));}
 
const int xn = 2e5 + 10;
const int xm = - 20 + 10;
const int sq = 320;
const int inf = 1e9 + 10;
const ll INF = 1e18 + 10;
const int mod = 998244353;
const int base = 257;

int n, m, sz[xn], par[xn], P[xn], H[xn];
int f[xn], sz2[xn];
pii E[xn];
ll ans;
vector <int> adj[xn], G[xn], vec;
bool mark[xn];

int get_root(int v){
	if (v == P[v])
		return v;
	return P[v] = get_root(P[v]);
}
void merge(int v, int u){
	v = get_root(v);
	u = get_root(u);
	if (v == u)
		return;
	if (sz[v] < sz[u])
		swap(v, u);
	P[u] = v;
	sz[v] += sz[u];
	if (H[f[u]] < H[f[v]])
		f[v] = f[u];
}

void DFS(int v){
	mark[v] = true;
	sz2[v] = 1;
	for (int u : adj[v]){
		if (mark[u]){
			if (H[u] >= H[v] || u == par[v])
				continue;
			int res = v;
			while (get_root(res) != get_root(u)){
				res = get_root(res);
				merge(f[res], par[f[res]]);
			}
			continue;
		}
		H[u] = H[v] + 1;
		par[u] = v;
		DFS(u);
		sz2[v] += sz2[u];
	}
}
void DFS2(int v, int s, int p = - 1){
	sz2[v] = sz[v];
	for (int u : G[v]){
		if (u == p)
			continue;
		DFS2(u, s, v);
		sz2[v] += sz2[u];
		ans -= 1LL * (sz[v] - 1) * (sz2[u]) * (sz2[u] + 1) + 1LL * sz2[u] * (sz2[u] - 1);
	}
	ans -= 1LL * (s - sz2[v]) * (s - sz2[v] + 1) * (sz[v] - 1) + 1LL * (s - sz2[v]) * (s - sz2[v] - 1);
}

int main(){
	InTheNameOfGod;
	
	cin >> n >> m;
	for (int i = 0; i < m; ++ i){
		int v, u;
		cin >> v >> u;
		adj[v].push_back(u);
		adj[u].push_back(v);
		E[i] = {v, u};
	}
	for (int i = 1; i <= n; ++ i){
		P[i] = f[i] = i;
		sz[i] = 1;
	}
	for (int i = 1; i <= n; ++ i){
		if (mark[i])
			continue;
		DFS(i);
		vec.push_back(i);
	}
	for (int i = 0; i < m; ++ i){
		int v = E[i].A, u = E[i].B;
		v = get_root(v);
		u = get_root(u);
		if (v == u)
			continue;
		G[v].push_back(u);
		G[u].push_back(v);
	}
	for (int v : vec)
		ans += 1LL * sz2[v] * (sz2[v] - 1) * (sz2[v] - 2), DFS2(v, sz2[v]);
	cout << ans << endl;
			
	return 0;
}

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• Subtask 4: 10 / 10
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