제출 #35697

#제출 시각아이디문제언어결과실행 시간메모리
35697funcsrJakarta Skyscrapers (APIO15_skyscraper)C++14
57 / 100
1000 ms28916 KiB
#include <cstdio>
#include <iostream>
#include <algorithm>
#include <string>
#include <cstring>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <cmath>
#include <iomanip>
#include <cassert>
#include <bitset>
using namespace std;

typedef pair<int, int> P;
typedef pair<int, P> P2;
#define rep(i, n) for (int i=0; i<(n); i++)
#define all(c) (c).begin(), (c).end()
#define uniq(c) c.erase(unique(all(c)), (c).end())
#define index(xs, x) (int)(lower_bound(all(xs), x) - xs.begin())
#define _1 first
#define _2 second
#define pb push_back
#define INF 1145141919
#define MOD 1000000007
const int B = 180;

int N, M;
vector<int> G[30000];
int D[30000][B+1];

signed main() {
  ios::sync_with_stdio(false); cin.tie(0);
  cin >> N >> M;
  rep(i, N) rep(j, B+1) D[i][j] = INF;
  int sx = 0, tx = 0;
  rep(i, M) {
    int b, p;
    cin >> b >> p;
    if      (i == 0) sx = b;
    else if (i == 1) tx = b;
    G[b].pb(p);
  }
  rep(i, N) sort(all(G[i])), uniq(G[i]);

  priority_queue<P2, vector<P2>, greater<P2> > q;
  D[sx][0] = 0;
  q.push(P2(0, P(sx, 0)));

  while (!q.empty()) {
    int x = q.top()._2._1,
        p = q.top()._2._2,
        r = q.top()._1; q.pop();
    if (D[x][p] < r) continue;

    if (p == 0) {
      for (int np : G[x]) {
        if (np <= B) {
          if (D[x][np] > r) {
            D[x][np] = r;
            q.push(P2(r, P(x, np)));
          }
        }
        else {
          for (int t=x%np; t<N; t+=np) {
            int cost = abs(x-t)/np;
            if (D[t][0] > r+cost) {
              D[t][0] = r+cost;
              q.push(P2(r+cost, P(t, 0)));
            }
          }
        }
      }
    }
    else {
      if (D[x][0] > r) {
        D[x][0] = r;
        q.push(P2(r, P(x, 0)));
      }
      if (x-p >= 0) {
        if (D[x-p][p] > r+1) {
          D[x-p][p] = r+1;
          q.push(P2(r+1, P(x-p, p)));
        }
      }
      if (x+p < N) {
        if (D[x+p][p] > r+1) {
          D[x+p][p] = r+1;
          q.push(P2(r+1, P(x+p, p)));
        }
      }
    }
  }
  int m = D[tx][0];
  if (m == INF) m = -1;
  cout << m << "\n";
  return 0;
}
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