Submission #35696

#	Time	Username	Problem	Language	Result	Execution time	Memory
35696		funcsr	Jakarta Skyscrapers (APIO15_skyscraper)	C++14	57 / 100	43 ms	32536 KiB

skyscraper

#include <cstdio>
#include <iostream>
#include <algorithm>
#include <string>
#include <cstring>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <cmath>
#include <iomanip>
#include <cassert>
#include <bitset>
using namespace std;

typedef pair<int, int> P;
typedef pair<int, P> P2;
#define rep(i, n) for (int i=0; i<(n); i++)
#define all(c) (c).begin(), (c).end()
#define uniq(c) c.erase(unique(all(c)), (c).end())
#define index(xs, x) (int)(lower_bound(all(xs), x) - xs.begin())
#define _1 first
#define _2 second
#define pb push_back
#define INF 1145141919
#define MOD 1000000007
const int B = 200;
const int LIM = 30100;

int N, M;
vector<int> G[30000];
int D[30000][B+1];
vector<P> Q[LIM];

signed main() {
  ios::sync_with_stdio(false); cin.tie(0);
  cin >> N >> M;
  rep(i, N) rep(j, B+1) D[i][j] = INF;
  int sx = 0, tx = 0;
  rep(i, M) {
    int b, p;
    cin >> b >> p;
    if      (i == 0) sx = b;
    else if (i == 1) tx = b;
    G[b].pb(p);
  }
  rep(i, N) sort(all(G[i])), uniq(G[i]);

  D[sx][0] = 0;
  Q[0].pb(P(sx, 0));

  rep(r, LIM) {
    while (!Q[r].empty()) {
      int x = Q[r].back()._1, p = Q[r].back()._2;
      Q[r].pop_back();
      if (D[x][p] < r) continue;

      if (p == 0) {
        for (int np : G[x]) {
          if (np <= B) {
            if (D[x][np] > r) {
              D[x][np] = r;
              Q[r].pb(P(x, np));
            }
          }
          else {
            for (int t=x%np; t<N; t+=np) {
              int cost = abs(x-t)/np;
              if (D[t][0] > r+cost) {
                D[t][0] = r+cost;
                Q[r+cost].pb(P(t, 0));
              }
            }
          }
        }
      }
      else {
        if (D[x][0] > r) {
          D[x][0] = r;
          Q[r].pb(P(x, 0));
        }
        if (x-p >= 0) {
          if (D[x-p][p] > r+1) {
            D[x-p][p] = r+1;
            Q[r+1].pb(P(x-p, p));
          }
        }
        if (x+p < N) {
          if (D[x+p][p] > r+1) {
            D[x+p][p] = r+1;
            Q[r+1].pb(P(x+p, p));
          }
        }
      }
    }
  }
  int m = D[tx][0];
  if (m == INF) m = -1;
  cout << m << "\n";
  return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 12 / 12
• Subtask 3: 14 / 14
• Subtask 4: 21 / 21
• Subtask 5: 0 / 43