/*
Proof of complexity: https://en.wikipedia.org/wiki/Circle_packing_in_a_square
*/
#include <bits/stdc++.h>
#define debug printf
#define ll long long
#define sz(x) (int)(x.size() )
#define all(x) x.begin(),x.end()
const int MAXN = 3e5+10 ;
using namespace std ;
struct Circle
{
ll x , y , r ;
Circle(ll x = 0 , ll y = 0 , ll r = 0 ) : x(x), y(y) , r(r) {}
} c[MAXN] ;
int N , idx ;
int ans[MAXN] , myBlock[MAXN] ;
ll meaning[MAXN] ;
ll G ;
vector<int> byY , byX ;
vector< pair<ll,int> > v[MAXN] ;
bool test(int i, int j )
{
ll dx = c[i].x - c[j].x ;
ll dy = c[i].y - c[j].y ;
ll dr = c[i].r + c[j].r ;
return dx*dx + dy*dy <= dr * dr ;
}
void rescale()
{
for(int i = 0 ; i <= idx ; i++ ) v[i].clear() ;
idx = -1 ;
for(int e : byX )
{
if(ans[e] != -1 ) continue ;
if(idx == -1 || (c[e].x/G) > meaning[idx] )
{
myBlock[e] = ++idx ;
meaning[idx] = (c[e].x/G) ;
}
else myBlock[e] = idx ;
}
for(int e : byY )
{
if(ans[e] != -1 ) continue ;
v[ myBlock[e] ].push_back(make_pair(c[e].y, e) ) ;
}
/*debug("Printing rescale with radio %d\n", G) ;
for(int i= 0 ; i <= idx ; i++ )
{
debug("In the x %d: ", meaning[i] ) ;
for(auto e : v[i] ) debug("%lld %d, ", e.first, e.second ) ;
debug("\n") ;
}*/
}
int main()
{
scanf("%d", &N ) ;
for(int i = 0 ; i < N ; i++ )
{
scanf("%lld %lld %lld", &c[i].x, &c[i].y, &c[i].r) ;
ans[i] = -1 ;
}
vector<int> byRadio(N) ; iota(all(byRadio), 0 );
sort(all(byRadio), [&](int i, int j)
{
if( c[i].r != c[j].r ) return c[i].r > c[j].r ;
return i< j ;
} ) ;
byY.resize(N) ; iota(all(byY),0) ;
sort(all(byY), [&](int i, int j ) { return c[i].y < c[j].y ; } ) ;
byX.resize(N) ; iota(all(byX), 0) ;
sort(all(byX), [&](int i, int j ) { return c[i].x < c[j].x ; } ) ;
G = c[ byRadio[0] ].r * 2LL + 1 ;
for(auto e : byRadio )
{
if( ans[e] != -1 ) continue ;
if( c[e].r*2LL < G )
{
G = c[e].r ;
rescale() ;
}
int l = max(0,myBlock[e]-2) ;
int r = min(myBlock[e]+2, idx ) ;
ll lo = c[e].y-2LL*c[e].r ;
ll hi = c[e].y+2LL*c[e].r ;
for(int i = l ; i <= r ; i++ )
{
int t = lower_bound(all(v[i]), make_pair(lo, -1 ) ) - v[i].begin() ;
for(; t < sz(v[i]) && v[i][t].first <= hi ; t++ )
{
if( ans[ v[i][t].second ] != -1 ) continue ;
if( test(v[i][t].second, e ) ) ans[ v[i][t].second ] = e ;
}
}
}
for(int i = 0 ; i < N ; i++ ) printf("%d ", ans[i]+1 ) ;
printf("\n") ;
}
