이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 7;
int n, m;
vector<int> g[N], g_[N];
int dep[N], low[N];
bool vis[N];
int cnt;
int sub[N];
long long ans = 0;
void prepare_dfs(int u, int par = -1) {
vis[u] = true;
low[u] = dep[u];
for (int v : g[u]) {
if (v == par)
continue;
if (!vis[v]) {
dep[v] = dep[u] + 1;
prepare_dfs(v, u);
low[u] = min(low[u], low[v]);
} else {
low[u] = min(low[u], dep[v]);
}
}
}
void add_edge(int u, int v, int c) {
g_[u].push_back(c);
g_[c].push_back(u);
g_[v].push_back(c);
g_[c].push_back(v);
}
void dfs(int u, int c = -1, int par = -1) {
vis[u] = true;
for (int v : g[u]) {
if (v == par)
continue;
if (!vis[v]) {
int c_ = c;
if (dep[u] <= low[v])
c_ = ++cnt;
add_edge(u, v, c_);
dfs(v, c_, u);
} else {
if (dep[u] > dep[v])
add_edge(u, v, c);
}
}
}
int get_subtree(int u, int par = -1) {
vis[u] = true;
sub[u] = u <= n;
for (int v : g[u]) {
if (v != par)
sub[u] += get_subtree(v, u);
}
return sub[u];
}
void count_bad(int u, int total, int par = -1) {
vis[u] = true;
for (int v : g[u]) {
if (v != par)
count_bad(v, total, u);
}
if (u > n) {
int a = g[u].size();
for (int v : g[u]) {
int b = v == par ? total - sub[u] : sub[v];
ans -= (long long)(a - 1) * b * (b - 1);
}
}
}
int main() {
#ifdef LOCAL
freopen("input.txt", "r", stdin);
#endif
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n >> m;
while (m--) {
int u, v;
cin >> u >> v;
g[u].push_back(v);
g[v].push_back(u);
}
for (int i = 1; i <= n; ++i)
vis[i] = false;
for (int i = 1; i <= n; ++i) {
if (!vis[i])
prepare_dfs(i);
}
for (int i = 1; i <= n; ++i)
vis[i] = false;
cnt = n;
for (int i = 1; i <= n; ++i) {
if (!vis[i])
dfs(i);
}
for (int i = 1; i <= cnt; ++i)
g[i] = g_[i];
for (int i = 1; i <= cnt; ++i) {
sort(g[i].begin(), g[i].end());
g[i].erase(unique(g[i].begin(), g[i].end()), g[i].end());
}
for (int i = 1; i <= cnt; ++i) {
if (!vis[i]) {
int total = get_subtree(i);
ans += (long long)total * (total - 1) * (total - 2);
count_bad(i, total);
}
}
cout << ans << endl;
return 0;
}
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