Submission #355389

#TimeUsernameProblemLanguageResultExecution timeMemory
355389spatarelCat in a tree (BOI17_catinatree)C++17
51 / 100
1004 ms312300 KiB
#include <stdio.h> #include <algorithm> #include <deque> #include <vector> const int MAX_N = 200000; int N, D; std::vector<int> children[MAX_N]; std::deque<int> maxN[MAX_N]; int depth[MAX_N]; void dfs(int u) { depth[u] = 1; //int deepestChild = -1; int secondDepth = 0; for (int v : children[u]) { dfs(v); if (depth[u] <= 1 + depth[v]) { secondDepth = depth[u]; depth[u] = 1 + depth[v]; //deepestChild = v; } else if (secondDepth < 1 + depth[v]) { secondDepth = 1 + depth[v]; } } maxN[u] = std::deque<int>(1 + D); maxN[u][0] = 1; for (int v : children[u]) { if (depth[v] > D - 1) { maxN[u][0] += maxN[v][D - 1]; } } std::vector<int> maxAdd(1 + D); for (int v : children[u]) { for (int d = 0; d < D && d < depth[v]; d++) { maxN[u][d + 1] += maxN[v][d]; } for (int d = 0; d < D - d - 2 && d < depth[v]; d++) { maxAdd[d + 1] = std::max(maxAdd[d + 1], maxN[v][d] - maxN[v][D - d - 2]); } } for (int d = 0; d < D - d - 2; d++) { maxN[u][d + 1] = maxAdd[d + 1] + maxN[u][D - d - 1]; } for (int d = D - 1; d >= 1; d--) { maxN[u][d - 1] = std::max(maxN[u][d - 1], maxN[u][d]); } /* printf("maxN[%d] = {", u); for (int d = 0; d < D; d++) { printf("%d, ", maxN[u][d]); } printf("}\n");//*/ } int main() { scanf("%d%d", &N, &D); for (int i = 1; i < N; i++) { int xi; scanf("%d", &xi); children[xi].push_back(i); } dfs(0); int answer = maxN[0][0]; printf("%d\n", answer); return 0; }

Compilation message (stderr)

catinatree.cpp: In function 'int main()':
catinatree.cpp:60:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   60 |   scanf("%d%d", &N, &D);
      |   ~~~~~^~~~~~~~~~~~~~~~
catinatree.cpp:63:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   63 |     scanf("%d", &xi);
      |     ~~~~~^~~~~~~~~~~
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