이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define ff(i,a,b) for(int i=a;i<=b;i++)
#define fb(i,b,a) for(int i=b;i>=a;i--)
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef pair<ll,int> pii;
const int maxn = 5005;
const int inf = 1e9 + 5;
template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k) print the k-th smallest number in os(0-based)
int n, k;
ll niz[maxn];
pii pom[maxn];
int dp[maxn];
int main()
{
ios::sync_with_stdio(false);
cout.tie(nullptr);
cin.tie(nullptr);
cin >> n >> k;
ff(i,1,n){
cin >> niz[i];
pom[i].fi = niz[i];
pom[i].se = i;
}
sort(pom + 1, pom + n + 1);
ff(i,0,n / k - 1){
ff(j,1,k)pom[j + i * k].fi = i + 1;
}
ff(i,1,n)niz[pom[i].se] = pom[i].fi;
ff(i,1,n){
fb(j,i - 1, 0){
if(niz[i] >= niz[j])dp[i] = max(dp[i], dp[j] + 1);
}
}
int rez = 0;
ff(i,1,n)rez = max(rez, dp[i]);
cout << n - rez << endl;
return 0;
}
/**
// probati bojenje sahovski ili slicno
**/
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