답안 #349575

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
349575 2021-01-17T21:06:12 Z CaroLinda Printed Circuit Board (CEOI12_circuit) C++14
85 / 100
100 ms 31084 KB
#include <bits/stdc++.h>
 
#pragma GCC optimization ("O2")
#pragma GCC optimization ("unroll-loops")
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma") 
#define sz(x) (int)(x.size())
#define debug printf
#define lp(i,a,b) for(int i = a ; i < b; i++)
#define pb push_back
#define ff first
#define ss second
#define mk make_pair
#define pii pair<int,int>
#define ll long long 
#define all(x) x.begin(),x.end()
 
const int MAX = 2e5+5 ;
 
using namespace std ;
 
char c ;
void readInt(int &num)
{
	num = 0 ;
	for(c = getchar() ; (c > 47 && c <58 ) ; c = getchar() )
		num = num*10 + c - 48 ;
}
 
void readLong(ll &num ) 
{
	num = 0 ;
	for(c = getchar() ; (c> 47 && c < 58 ) ; c = getchar() )
		num = num*10 + c - 48 ;
}
 
int N ;
int myId[MAX] ;
ll num[MAX], den[MAX] ;
 
struct Point
{
 
    ll x , y ;
 
    Point(ll x=0, ll y=0):x(x), y(y) {}
    
    bool operator == ( Point other ) const { return x == other.x && y == other.y ; }
    bool operator != (Point other ) const { return x != other.x || y != other.y ; }
    Point operator - (Point other) const { return Point(x-other.x, y-other.y) ; } 
    ll operator % (Point other) const { return x*other.y - y*other.x ; }
    ll operator *(Point other) const { return x*other.x + y*other.y ; }
    void read() { scanf("%lld %lld", &x, &y) ; }
} ;
 
struct Line
{
	Point p1, p2 ; 
	ll cte ;
	Line( Point p1 = Point(0,0) , Point p2 = Point(0,0) ) : p1(p1) , p2(p2) {} 
} t ;
 

ll q1, q2, r1, r2 ;
bool isLess(ll num1, ll den1, ll num2, ll den2 )
{
	//It doesn't happen that den < 0, because x is always positive 
	q1 = num1/den1 ;
	q2 = num2/den2 ;
	r1 = num1%den1 ;
	r2 = num2%den2 ;
 
	if( q1 != q2 ) return q1 < q2 ;
	if( r1 == 0 || r2 == 0 ) return r1 == 0 && r2 > 0 ;
 
	return isLess(den2, r2, den1, r1 ) ;
} 
ll cte , dx , dy ;

double num1, num2, den1, den2 ;

struct Seg
{
 
	Line tree[MAX*2] ;
	int n ;
	int l[MAX*2], r[MAX*2] ;
 
	void ini()
	{
		for(int i= n ; i < 2*n ; i++ ) l[i] = r[i] = i - n ;
 
		for(int i= n-1 ; i > 0 ; i-- )
		{
			l[i] = min(l[i<<1], l[i<<1|1] ) ;
			r[i] = max(r[i<<1], r[i<<1|1] ) ;
		}
 
	}
 
	void upd(int pos )
	{
		if( tree[pos].p1 == Point(0,0) ) return (void)(tree[pos] = t ) ; 
			 
		ll auxDx = (tree[pos].p1.x - tree[pos].p2.x ) ;
		ll auxDy = (tree[pos].p1.y - tree[pos].p2.y ) ;
 
		for(auto e : {l[pos] , r[pos] } ) 
		{
			num1 = den[e] * tree[pos].cte ;
			den1 = den[e] * auxDy - num[e] * auxDx ;
			num2 = den[e] * t.cte ;
			den2 = den[e] * dy - num[e] * dx ;
 
			if( tree[pos].p1.x == tree[pos].p2.x ) num1 = tree[pos].p1.x, den1 = 1LL ;
			if(t.p1.x == t.p2.x ) num2 = t.p1.x , den2 = 1LL ;
 
			if( (num1/den1) < (num2/den2) ) return ;
 
		}
		tree[pos] = t ;
 
	}
 
	void addLine(int l, int r )
	{
		dy = ( t.p1.y - t.p2.y ) ;
		dx = (t.p1.x-t.p2.x ) ;
 
		for( l += n , r += n ; l < r ; l >>= 1 , r >>= 1 )
		{
			if(l&1) 
			{
				upd(l) ;
				l++ ;
			}
			if(r&1) upd(--r) ;
		}			
	}
 
	bool qry(int pos, Point p )
	{
		for(pos += n ; pos > 0 ; pos >>= 1 )
		{
			if( tree[pos].p1 == Point(0,0) || tree[pos].p1 == p || tree[pos].p2 == p ) continue ;	
 
			ll val1 = (tree[pos].p2 - tree[pos].p1)%(p-tree[pos].p1) ;
			ll val2 = (tree[pos].p2-tree[pos].p1)%(Point(0,0)-tree[pos].p1 ) ;
 
			if( (val1 < 0 ) != (val2 < 0)  ) return false ;
			
		}
 
		return true ;
	}
  
} seg ;
 
int main()
{
 
	readInt(N) ;
		 
	vector<Point> p(N) ;
	vector< pair<Point, int> > sorted ;
 
	for(int i = 0 ; i < N ; i++ ) 
	{
		readLong(p[i].x ) ;
		readLong(p[i].y ) ;
		sorted.push_back( make_pair(p[i], i ) ) ;
	}
 
 	sort(all(sorted), [&]( pair<Point,int> a, pair<Point,int> b ) 
	{
		if( a.first%b.first == 0 ) return (b.first-a.first)*(Point(0,0)-a.first ) < 0 ;
		return a.first%b.first > 0 ;	
	} ) ; 
 
	int j = -1 ;
	for(int i = 0 ; i < N ; i++ ) 
	{
	   if(!i || sorted[i-1].first%sorted[i].first != 0 ) j++ ;
	   		
		myId[ sorted[i].second ] = j ;
 
		num[j] = sorted[i].first.y ;
		den[j] = sorted[i].first.x ;
	}
 
   seg.n = j+1 ;
	seg.ini() ;		
 
	for(int i = 0 , nxt = 1 ; i < N ; i++, nxt++ )
	{
		if(nxt ==  N ) nxt = 0 ;
 
		int l = myId[i] , r = myId[nxt] ;
 
      if(l == r ) continue ;
		if( l > r ) swap(l,r) ;
 
      t.p1 = p[i] ;
      t.p2 = p[nxt] ;
      t.cte = ( t.p1.y*t.p2.x - t.p1.x*t.p2.y ) ;
 
		seg.addLine(l,r+1 ) ;  
 
	} 
 
 
	//Don't forget to check if there is someone in the same polar angle that mine (because, if there is, it fucks everything up )
 
	vector<int> ans ;
	for(int i=0 ; i < N ; i++ )
	{
		if(i && sorted[i-1].first%sorted[i].first == 0 ) continue ;
		if(seg.qry(myId[ sorted[i].second ] , sorted[i].first ) ) ans.push_back(sorted[i].second ) ;
	}
 
	sort(all(ans) ) ;
 
	printf("%d\n", sz(ans ) ) ;
	for(auto e : ans ) printf("%d ", e+1 ) ;
	printf("\n") ;
 
 
}

Compilation message

circuit.cpp:3: warning: ignoring #pragma GCC optimization [-Wunknown-pragmas]
    3 | #pragma GCC optimization ("O2")
      | 
circuit.cpp:4: warning: ignoring #pragma GCC optimization [-Wunknown-pragmas]
    4 | #pragma GCC optimization ("unroll-loops")
      |
# 결과 실행 시간 메모리 Grader output
1 Correct 11 ms 16128 KB Output is correct
2 Correct 13 ms 16108 KB Output is correct
3 Correct 12 ms 16384 KB Output is correct
4 Correct 13 ms 16364 KB Output is correct
5 Correct 16 ms 16872 KB Output is correct
6 Correct 18 ms 16872 KB Output is correct
7 Correct 23 ms 17636 KB Output is correct
8 Correct 15 ms 16688 KB Output is correct
9 Correct 15 ms 16744 KB Output is correct
10 Correct 17 ms 16872 KB Output is correct
11 Correct 17 ms 17000 KB Output is correct
12 Correct 19 ms 17636 KB Output is correct
13 Correct 30 ms 18404 KB Output is correct
14 Correct 29 ms 19040 KB Output is correct
15 Correct 32 ms 19808 KB Output is correct
16 Correct 55 ms 23516 KB Output is correct
17 Correct 90 ms 23516 KB Output is correct
18 Execution timed out 103 ms 30928 KB Time limit exceeded
19 Execution timed out 105 ms 30928 KB Time limit exceeded
20 Execution timed out 202 ms 31084 KB Time limit exceeded