이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "race.h"
#define fi first
#define se second
#define maxn 200000
#define maxk 1000001
#define pb push_back
using namespace std;
typedef pair<int,int> pi;
int n,k,ans;
int sz[maxn];
int dist[maxn];
int depth[maxn];
bool mark[maxn];
int minDepth[maxk];
vector<int> nodes;
vector<pi> adj[maxn];
int dfs(int u , int dad , int de , int di) {
sz[u] = 1;
nodes.pb(u);
int deg = adj[u].size();
for( int i = 0 ; i < deg ; i++ ) {
int v = adj[u][i].fi;
int vdi = di + adj[u][i].se;
if(v != dad && !mark[v])
sz[u] += dfs(v,u,de+1,vdi);
}
return sz[u];
}
void Dfs(int u) {
nodes.clear();
dfs(u,-1,0,0);
}
int findRoot() {
int nsz = nodes.size();
int root = nodes[0];
int minSz = sz[root];
int limit = (nsz+1) / 2;
for( int i = 1 ; i < nsz ; i++ ) {
int u = nodes[i];
if(sz[u] >= limit && sz[u] < minSz) {
root = u;
minSz = sz[u];
}
}
return root;
}
void solve(int u) {
Dfs(u);
u = findRoot();
mark[u] = true;
int deg = adj[u].size();
vector<int> rem;
for( int i = 0 ; i < deg ; i++ ) {
int v = adj[u][i].fi;
int d = adj[u][i].se;
if(!mark[v]) {
Dfs(v);
vector<pi> upd;
int nsz = nodes.size();
for( int j = 0 ; j < nsz ; j++ ) {
int w = nodes[j];
int wDist = dist[w] + d;
int wDepth = depth[w] + 1;
if(wDist <= k) {
rem.pb(wDist);
upd.pb(pi(wDist,wDepth));
int remDist = k-wDist;
if(minDepth[remDist] != -1)
ans = min(ans,minDepth[remDist]+wDepth);
}
if(wDist == k)
ans = min(ans,wDepth);
}
int nupd = upd.size();
for( int j = 0 ; j < nupd ; j++ ) {
int key = upd[j].fi;
int val = upd[j].se;
if(minDepth[key] == -1 || val < minDepth[key])
minDepth[key] = val;
}
}
}
int r = rem.size();
for( int i = 0 ; i < r ; i++ )
minDepth[rem[i]] = -1;
for( int i = 0 ; i < deg ; i++ ) {
int v = adj[u][i].fi;
if(!mark[v])
solve(v);
}
}
int best_path(int N, int K, int e[][2], int c[]) {
n = N;
k = K;
ans = n+1;
for( int i = 0 ; i < n-1 ; i++ ) {
int u = e[i][0];
int v = e[i][1];
int d = c[i];
adj[u].pb(pi(v,d));
adj[v].pb(pi(u,d));
}
memset(minDepth,-1,sizeof(minDepth));
solve(0);
return (ans < n) ? ans : -1;
}
/*
int main() {
int n = 4 , k = 3;
int e[3][2];
e[0][0] = 0 , e[0][1] = 1;
e[1][0] = 1 , e[1][1] = 2;
e[2][0] = 1 , e[2][1] = 3;
int d[3];
d[0] = 1;
d[1] = 2;
d[2] = 4;
printf("%d\n",best_path(n,k,e,d));
return 0;
}
*/
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