Submission #348683

#	Time	Username	Problem	Language	Result	Execution time	Memory
348683		Sho10	Simple (info1cup19_simple)	C++14	30 / 100	450 ms	22124 KiB

subway

#include <bits/stdc++.h> //Andrei Alexandru a.k.a Sho10
#define ll long long 
#define double long double
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#define aint(a) (a).begin(), (a).end()
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define pi pair
#define rc(s) return cout<<s,0
#define endl '\n'
#define mod 1000000007
#define PI 3.14159265359
#define MAXN 100005
#define INF 1000000005
#define LINF 1000000000000000005ll
#define CODE_START  ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
using namespace std;
ll n,q,a[200005],lazy[1000005];
pair<ll,ll>mx[1000005],mn[1000005];
void build(ll node,ll l,ll r){
	if(l==r){
		if(a[l]%2==1){
			mx[node].f=-1;
			mx[node].s=a[l];
			mn[node].f=LINF-1;
			mn[node].s=a[l];
		}else {
			mx[node].f=a[l];
			mx[node].s=-1;
			mn[node].f=a[l];
			mn[node].s=LINF-1;
		}
		return;
	}
	ll mid=(l+r)/2;
	build(2*node,l,mid);
	build(2*node+1,mid+1,r);
	mx[node].f=max(mx[2*node].f,mx[2*node+1].f);
	mx[node].s=max(mx[2*node].s,mx[2*node+1].s);
	mn[node].f=min(mn[2*node].f,mn[2*node+1].f);
	mn[node].s=min(mn[2*node].s,mn[2*node+1].s);
}
void update(ll node,ll l,ll r,ll st,ll dr,ll val){
	if(l>r){
		return;
	}
	if(r<st){
		return;
	}
	if(l>dr){
		return;
	}
	if(lazy[node]!=0){
		ll x=lazy[node];
		if(mx[node].f!=-1){
		mx[node].f+=x;
	}
	if(mx[node].s!=-1){
		mx[node].s+=x;
	}
	if(mn[node].f!=LINF-1){
		mn[node].f+=x;
	}
	if(mn[node].s!=LINF-1){
		mn[node].s+=x;
	}
	if(x%2==1){
		swap(mn[node].f,mn[node].s);
		swap(mx[node].f,mx[node].s);
	}
		if(l!=r){
			lazy[2*node]+=x;
			lazy[2*node+1]+=x;
		}
		lazy[node]=0;
	}
	if(st<=l&&r<=dr){
		ll x=val;
		if(mx[node].f!=-1){
		mx[node].f+=x;
	}
	if(mx[node].s!=-1){
		mx[node].s+=x;
	}
	if(mn[node].f!=LINF-1){
		mn[node].f+=x;
	}
	if(mn[node].s!=LINF-1){
		mn[node].s+=x;
	}
	if(x%2==1){
		swap(mn[node].f,mn[node].s);
		swap(mx[node].f,mx[node].s);
	}
		if(l!=r){
			lazy[2*node]+=val;
			lazy[2*node+1]+=val;
		}
		return;
	}
	ll mid=(l+r)/2;
	update(2*node,l,mid,st,dr,val);
	update(2*node+1,mid+1,r,st,dr,val);
	mx[node].f=max(mx[2*node].f,mx[2*node+1].f);
	mx[node].s=max(mx[2*node].s,mx[2*node+1].s);
	mn[node].f=min(mn[2*node].f,mn[2*node+1].f);
	mn[node].s=min(mn[2*node].s,mn[2*node+1].s);
}
ll query1(ll node,ll l,ll r,ll st,ll dr){
	if(l>r){
		return LINF;
	}
	if(l>dr){
		return LINF;
	}
	if(r<st){
		return LINF;
	}
	if(lazy[node]!=0){
		ll x=lazy[node];
		if(mx[node].f!=-1){
		mx[node].f+=x;
	}
	if(mx[node].s!=-1){
		mx[node].s+=x;
	}
	if(mn[node].f!=LINF-1){
		mn[node].f+=x;
	}
	if(mn[node].s!=LINF-1){
		mn[node].s+=x;
	}
	if(x%2==1){
		swap(mn[node].f,mn[node].s);
		swap(mx[node].f,mx[node].s);
	}
		if(l!=r){
			lazy[2*node]+=x;
			lazy[2*node+1]+=x;
		}
		lazy[node]=0;
	}
	if(st<=l&&r<=dr){
		return mn[node].f;
	}
	ll mid=(l+r)/2;
	return min(query1(2*node,l,mid,st,dr),query1(2*node+1,mid+1,r,st,dr));
}
ll query2(ll node,ll l,ll r,ll st,ll dr){
	if(l>r){
		return -1;
	}
	if(l>dr){
		return -1;
	}
	if(r<st){
		return -1;
	}
	if(lazy[node]!=0){
		ll x=lazy[node];
		if(mx[node].f!=-1){
		mx[node].f+=x;
	}
	if(mx[node].s!=-1){
		mx[node].s+=x;
	}
	if(mn[node].f!=LINF-1){
		mn[node].f+=x;
	}
	if(mn[node].s!=LINF-1){
		mn[node].s+=x;
	}
	if(x%2==1){
		swap(mn[node].f,mn[node].s);
		swap(mx[node].f,mx[node].s);
	}
		if(l!=r){
			lazy[2*node]+=x;
			lazy[2*node+1]+=x;
		}
		lazy[node]=0;
	}
	if(st<=l&&r<=dr){
		return mx[node].s;
	}
	ll mid=(l+r)/2;
	return max(query2(2*node,l,mid,st,dr),query2(2*node+1,mid+1,r,st,dr));
}
int32_t main(){
CODE_START;
cin>>n;
for(ll i=1;i<=n;i++)
{
	cin>>a[i];
}
build(1,1,n);
cin>>q;
while(q--){
	ll type;
	cin>>type;
	if(type==0){
		ll l,r,val;
		cin>>l>>r>>val;
		update(1,1,n,l,r,val);
	}else {
		ll l,r;
		cin>>l>>r;
		ll s1=query1(1,1,n,l,r);
		if(s1==LINF-1){
		    s1=-1;
		}
		cout<<s1<<' ';
		s1=query2(1,1,n,l,r);
		if(s1==0){
		    s1=-1;
		}
		cout<<s1<<endl;
	}
}
}
	
 

• Subtask 1: 0 / 30
• Subtask 2: 30 / 30
• Subtask 3: 0 / 40