제출 #347227

#제출 시각아이디문제언어결과실행 시간메모리
347227BorisBarcaMatching (CEOI11_mat)C++14
0 / 100
476 ms61060 KiB
/* $$$$$$$\ $$\ $$$$$$$\ $$ __$$\ \__| $$ __$$\ $$ | $$ | $$$$$$\ $$$$$$\ $$\ $$$$$$$\ $$ | $$ | $$$$$$\ $$$$$$\ $$$$$$$\ $$$$$$\ $$$$$$$\ |$$ __$$\ $$ __$$\ $$ |$$ _____|$$$$$$$\ | \____$$\ $$ __$$\ $$ _____|\____$$\ $$ __$$\ $$ / $$ |$$ | \__|$$ |\$$$$$$\ $$ __$$\ $$$$$$$ |$$ | \__|$$ / $$$$$$$ | $$ | $$ |$$ | $$ |$$ | $$ | \____$$\ $$ | $$ |$$ __$$ |$$ | $$ | $$ __$$ | $$$$$$$ |\$$$$$$ |$$ | $$ |$$$$$$$ |$$$$$$$ |\$$$$$$$ |$$ | \$$$$$$$\\$$$$$$$ | \_______/ \______/ \__| \__|\_______/ \_______/ \_______|\__| \_______|\_______| */ #include <bits/stdc++.h> #include <ext/pb_ds/detail/standard_policies.hpp> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; #define PB push_back #define MP make_pair #define INS insert #define LB lower_bound #define UB upper_bound #define pii pair <int,int> #define pll pair <long long, long long> #define X first #define Y second #define _ << " " << #define sz(x) (int)x.size() #define all(a) (a).begin(),(a).end() #define FOR(i, a, b) for (int i = (a); i < (b); ++i) #define FORD(i, a, b) for (int i = (a); i > (b); --i) #define FORA(i, x) for (auto &i : x) #define REP(i, n) FOR(i, 0, n) #define BITS(x) __builtin_popcount(x) #define SQ(a) (a) * (a) #define TRACE(x) cout << #x " = " << (x) << '\n'; #define YES cout << "YES\n" #define NO cout << "NO\n" #define umap unordered_map typedef long long ll; typedef long double ld; typedef vector <int> vi; typedef vector <pii> vpi; typedef vector <ll> vll; typedef vector <pll> vpl; typedef vector <double> vd; typedef vector <ld> vld; typedef vector<string> vs; typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update>ordered_set; //find_by_order -> kti najmanji //order_of_key -> koliko ima manjih od x //((float) t)/CLOCKS_PER_SEC const int MOD = 1e9 + 7; const double PI = acos(-1); const int INF = 1e9 + 10; const ll INFL = 1e18 + 10; const int ABC = 30; const int dx[] = {-1, 1, 0, 0}; const int dy[] = {0, 0, -1, 1}; const int dox[] = {-1, 1, 0, 0, -1, -1, 1, 1}; const int doy[] = {0, 0, -1, 1, -1, 1, -1, 1}; inline int sum(int a, int b){ if (a + b < 0) return (a + b + MOD) % MOD; return (a + b) % MOD; } inline void add(int &a, int b){ a = sum(a, b); } inline int mul(ll a, ll b){ return ((a % MOD) * ((ll)b % MOD)) % MOD; } inline int sub(int a, int b){ return (a - b + MOD) % MOD; } inline int fast_pot(ll pot, ll n){ ll ret = 1; while (n){ if (n & 1LL) ret = (ret * pot) % MOD; pot = (pot * pot) % MOD; n >>= 1LL; } return ret; } inline int divide(int a, int b){ return mul(a, fast_pot(b, MOD - 2)); } ll lcm(ll a, ll b){ return abs(a * b) / __gcd(a, b); } inline double ccw(pii A, pii B, pii C){ return (A.X * B.Y) - (A.Y * B.X) + (B.X * C.Y) - (B.Y * C.X) + (C.X * A.Y) - (C.Y * A.X); } inline int CCW(pii A, pii B, pii C){ double val = ccw(A, B, C); double eps = max(max(abs(A.X), abs(A.Y)), max(max(abs(B.X), abs(B.Y)), max(abs(C.X), abs(C.Y)))) / 1e9; if (val <= -eps) return -1; if (val >= eps) return 1; return 0; } void to_upper(string &x){ REP(i, sz(x)) x[i] = toupper(x[i]); } void to_lower(string &x){ REP(i, sz(x)) x[i] = tolower(x[i]); } string its(ll x){ if (x == 0) return "0"; string ret = ""; while (x > 0){ ret += (x % 10) + '0'; x /= 10; } reverse(all(ret)); return ret; } ll sti(string s){ ll ret = 0; REP(i, sz(s)){ ret *= 10; ret += (s[i] - '0'); } return ret; } const int N = 1e6 + 10; const int P = 101; const int LOG = 20; const int OFF = 1 << LOG; int n, m, pot[N], a[N], b[N], ans[N]; struct node{ int cnt, p, h; }; struct tournament{ node t[3 * OFF]; int off; void init(int n){ for (off = 1; off < n; off *= 2); REP(i, 2 * OFF) t[i].cnt = t[i].p = t[i].h = 0; } void update(int x, int c, int p){ t[x + off].cnt = c; t[x + off].p = p; t[x + off].h = 0; for (int i = (x + off) / 2; i; i /= 2){ t[i].p = sum(t[i * 2].p, t[i * 2 + 1].p); t[i].h = sum(t[i * 2].h, t[i * 2 + 1].h); add(t[i].h, mul(t[i * 2 + 1].p, t[i * 2].cnt)); t[i].cnt = sum(t[i * 2].cnt, t[i * 2 + 1].cnt); } } } T; int main () { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); pot[0] = 1; FOR(i, 1, N) pot[i] = mul(pot[i - 1], P); cin >> n >> m; int H = 0; REP(i, n){ ll x; cin >> x; a[i] = x; ans[x - 1] = i; } REP(i, n){ //cout << ans[i] << ' '; add(H, mul(pot[n - i - 1], ans[i])); } //cout << '\n'; set <ll> sor; REP(i, m){ ll x; cin >> x; b[i] = x; sor.INS(x); } return 0; map <ll, int> idx; int cnt = 0; FORA(x, sor) idx[x] = cnt++; T.init(m); REP(i, n) T.update(idx[b[i]], 1, pot[m - i - 1]); vi sol; REP(i, (m - n) + 1){ //cout << i _ pomH[i] << '\n'; //cout << (mul(pomH[i], H) == T.t[1].h) << '\n'; if (mul(pot[(m - n) - i], H) == T.t[1].h){ //cout << "da tako je\n"; //cout << "dodajem jebeni" _ i <<'\n'; sol.PB(i); } T.update(idx[b[i]], 0, 0); T.update(idx[b[i + n]], 1, pot[m - (i + n) - 1]); } cout << sz(sol) << '\n'; FORA(x, sol) cout << x + 1 << ' '; cout << '\n'; return 0; }
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