이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
using namespace std;
const int MAXN = (int)1e5 + 5;
const ll INF = (ll)1e18;
ll x[3][MAXN];
ll y[3][MAXN];
ll n, k;
ll dup(ll a, ll b) {
return (a + b - 1ll) / b;
}
ll S(ll x) {
return x * x;
}
ll sz_of_corner(ll n, ll len) {
return (S(dup(n / len, 2)) + S((n / len) / 2ll)) * (len * len);
}
ll solve(ll len) {
if (n == len) {
return INF;
}
ll bad_white[2] = {0, 0};
ll good_black[2] = {0, 0};
for (int i = 1; i <= k; i++) {
assert(x[1][i] == x[2][i] && y[1][i] == y[2][i]);
int xx = dup(x[1][i], len);
int yy = dup(y[1][i], len);
// в правом левом углу черный цвет
if ((xx + yy) % 2 == 0) { // черный цвет
good_black[1]++;
} else { // белый
bad_white[1]++;
}
// в правом левом углу белый цвет
if ((xx + yy) % 2 == 0) { // белый цвет
bad_white[0]++;
} else { // черный
good_black[0]++;
}
}
return min(bad_white[1] + sz_of_corner(n, len) - good_black[1],
bad_white[0] + ((S(n) - sz_of_corner(n, len)) - good_black[0]));
}
signed main() {
ios_base::sync_with_stdio(0); cin.tie(0);
cin >> n >> k;
for (int i = 1; i <= k; i++) {
cin >> x[1][i] >> y[1][i] >> x[2][i] >> y[2][i];
}
ll ans = INF;
for (int i = 1; i * i <= n; i++) {
if (n % i == 0) {
ans = min(ans, solve(i));
ans = min(ans, solve(n / i));
}
}
cout << ans << endl;
}
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