제출 #345889

#제출 시각아이디문제언어결과실행 시간메모리
345889ACmachine캥거루 (CEOI16_kangaroo)C++17
51 / 100
1640 ms524292 KiB
#include <bits/stdc++.h> using namespace std; #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; template<typename T, typename U> using ordered_map = tree<T, U, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long ll; typedef long double ld; typedef double db; typedef string str; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef vector<int> vi; typedef vector<ll> vll; typedef vector<pii> vpii; typedef vector<pll> vpll; typedef vector<str> vstr; #define FOR(i,j,k,in) for(int i=(j); i < (k);i+=in) #define FORD(i,j,k,in) for(int i=(j); i >=(k);i-=in) #define REP(i,b) FOR(i,0,b,1) #define REPD(i,b) FORD(i,b,0,1) #define pb push_back #define mp make_pair #define ff first #define ss second #define all(x) begin(x), end(x) #define rsz resize #define MANY_TESTS int tcase; cin >> tcase; while(tcase--) const double EPS = 1e-9; const int MOD = 1e9+7; // 998244353; const ll INFF = 1e18; const int INF = 1e9; const ld PI = acos((ld)-1); const vi dy = {1, 0, -1, 0, -1, 1, 1, -1}; const vi dx = {0, 1, 0, -1, -1, 1, -1, 1}; #ifdef DEBUG #define DBG if(1) #else #define DBG if(0) #endif #define dbg(x) cout << "(" << #x << " : " << x << ")" << endl; // ostreams template <class T, class U> ostream& operator<<(ostream& out, const pair<T, U> &par) {out << "[" << par.first << ";" << par.second << "]"; return out;} template <class T> ostream& operator<<(ostream& out, const set<T> &cont) { out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; } template <class T, class U> ostream& operator<<(ostream& out, const map<T, U> &cont) {out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; } template<class T> ostream& operator<<(ostream& out, const vector<T> &v){ out << "["; REP(i, v.size()) out << v[i] << ", "; out << "]"; return out;} // istreams template<class T> istream& operator>>(istream& in, vector<T> &v){ for(auto &x : v) in >> x; return in; } template<class T, class U> istream& operator>>(istream& in, pair<T, U> &p){ in >> p.ff >> p.ss; return in; } //searches template<typename T, typename U> T bsl(T lo, T hi, U f){ hi++; T mid; while(lo < hi){ mid = (lo + hi)/2; f(mid) ? hi = mid : lo = mid+1; } return lo; } template<typename U> double bsld(double lo, double hi, U f, double p = 1e-9){ int r = 3 + (int)log2((hi - lo)/p); double mid; while(r--){ mid = (lo + hi)/2; f(mid) ? hi = mid : lo = mid; } return (lo + hi)/2; } template<typename T, typename U> T bsh(T lo, T hi, U f){ lo--; T mid; while(lo < hi){ mid = (lo + hi + 1)/2; f(mid) ? lo = mid : hi = mid-1; } return lo; } template<typename U> double bshd(double lo, double hi, U f, double p = 1e-9){ int r = 3+(int)log2((hi - lo)/p); double mid; while(r--){ mid = (lo + hi)/2; f(mid) ? lo = mid : hi = mid; } return (lo + hi)/2; } // some more utility functions template<typename T> pair<T, int> get_min(vector<T> &v){ typename vector<T> :: iterator it = min_element(v.begin(), v.end()); return mp(*it, it - v.begin());} template<typename T> pair<T, int> get_max(vector<T> &v){ typename vector<T> :: iterator it = max_element(v.begin(), v.end()); return mp(*it, it - v.begin());} template<typename T> bool ckmin(T& a, const T& b){return b < a ? a = b , true : false;} template<typename T> bool ckmax(T& a, const T& b){return b > a ? a = b, true : false;} const int mod = (int)1e9+7; struct Mint{ int val; Mint(){ val = 0; } Mint(long long v){ val = (-mod <= v && v < mod) ? v : v%mod; if(val < 0) val+= mod; } // operators Mint operator-(){return Mint(-val);} Mint& operator+=(const Mint& other){ val+=other.val; if(val >= mod) val-=mod; return *this;} Mint& operator-=(const Mint& other){ val-=other.val; if(val < 0) val+=mod; return *this;} Mint& operator*=(const Mint& other){ val=((long long)val*other.val)%mod; return *this;} friend Mint binpow(Mint a, long long p){ Mint res(1); while(p > 0){ if(p&1) res*=a; a*=a; p>>=1; } return res; } friend Mint inv(Mint a){ return binpow(a, mod-2); } Mint& operator/=(const Mint &other){ return (*this)*=inv(other);} friend Mint operator+(Mint a, const Mint& b){ return a+=b; } friend Mint operator-(Mint a, const Mint& b){ return a-=b; } friend Mint operator*(Mint a, const Mint& b){ return a*=b; } friend Mint operator/(Mint a, const Mint& b){ return a/=b; } bool operator==(const Mint &other){return val == other.val;} bool operator!=(const Mint &other){return val != other.val;} bool operator<(const Mint &other){return val < other.val;} // io friend ostream& operator<<(ostream &out, Mint &a){ return out << a.val; } }; // try for 51 int main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n, cs, cf; cin >> n >> cs >> cf; cs--; cf--; if(cs > cf) swap(cs, cf); vector<vector<vector<Mint>>> A(n + 1, vector<vector<Mint>>(n, vector<Mint>(n, Mint(0)))); vector<vector<vector<Mint>>> D(n + 1, vector<vector<Mint>>(n, vector<Mint>(n, Mint(0)))); A[2][0][1] = Mint(1); D[2][1][0] = Mint(1); FOR(k, 3, n+1, 1){ REP(i, k){ REP(j, k){ if(i == j) continue; FOR(g, i, k - 1, 1){ if(i < j){ A[k][i][j] += D[k-1][g][j-1]; } else{ A[k][i][j] += D[k-1][g][j]; } } REP(g, i){ if(i < j){ D[k][i][j] += A[k - 1][g][j - 1]; } else{ D[k][i][j] += A[k-1][g][j]; } } } } /* dbg(k) */ /* cout << "A:\n"; */ /* REP(i, k){ */ /* REP(j, k){ */ /* cout << i << " " << j << " " << A[k][i][j] << "\n"; */ /* } */ /* } */ /* cout << "B:\n"; */ /* REP(i, k){ */ /* REP(j, k){ */ /* cout << i << " " << j << " " << D[k][i][j] << "\n"; */ /* } */ /* } */ } Mint ans = A[n][cs][cf] + D[n][cs][cf]; cout << ans << "\n"; return 0; }

컴파일 시 표준 에러 (stderr) 메시지

kangaroo.cpp: In function 'Mint binpow(Mint, long long int)':
kangaroo.cpp:100:13: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
  100 |             if(p&1) res*=a; a*=a; p>>=1;
      |             ^~
kangaroo.cpp:100:29: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
  100 |             if(p&1) res*=a; a*=a; p>>=1;
      |                             ^
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