제출 #345343

#제출 시각아이디문제언어결과실행 시간메모리
345343mohamedsobhi777Hacker (BOI15_hac)C++14
0 / 100
1 ms512 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #pragma GCC optimize("-Ofast") //#pragma GCC optimize("trapv") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,sse4.2,popcnt,abm,mmx,avx2,tune=native") #pragma GCC optimize("-ffast-math") #pragma GCC optimize("-funroll-loops") using namespace std; using namespace __gnu_pbds; #define vi vector<int> #define vll vector<ll> #define vii vector<pair<int, int>> #define vvi vector<vi> #define vvii vector<vii> #define pii pair<int, int> #define pll pair<ll, ll> #define loop(_) for (int __ = 0; __ < (_); ++__) #define forn(i, n) for (int i = 0; i < n; ++i) #define pb push_back #define f first #define s second #define sz(_) ((int)_.size()) #define all(_) _.begin(), _.end() #define uni(_) unique(_) #define lb lower_bound #define ub upper_bound #define si set<int> #define ms multiset<int> #define qi queue<int> #define pq prioriry_queue<int> #define mi map<int, int> #define inc(i, l, r) for (int i = l; i <= r; i++) #define dec(i, l, r) for (int i = l; i >= r; i--) using lll = __int128; using ll = long long; using ld = long double; const int N = 1e5 + 7; const ll mod = 1e9 + 7; const ll inf = 2e18; auto ra = [] {char *p = new char ; delete p ; return ll(p) ; }; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count() * (ra() | 1)); typedef tree<pii, null_type, less<pii>, rb_tree_tag, tree_order_statistics_node_update> os; __int128 read() { __int128 x = 0, f = 1; char ch = getchar(); while (ch < '0' || ch > '9') { if (ch == '-') f = -1; ch = getchar(); } while (ch >= '0' && ch <= '9') { x = x * 10 + ch - '0'; ch = getchar(); } return x * f; } void print(__int128 x) { if (x < 0) { putchar('-'); x = -x; } if (x > 9) print(x / 10); putchar(x % 10 + '0'); } bool cmp(__int128 x, __int128 y) { return x > y; } int n; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> n; vll a(n); for (auto &u : a) cin >> u; ll ans = 0; int t = (n + 1) / 2; for (int i = 0; i < n; ++i) a.pb(a[i]); for (int i = 1; i < 2 * n; ++i) a[i] += a[i - 1]; auto get = [&](int l, int r) -> ll { return a[r] - (l ? a[l - 1] : 0); }; for (int i = t - 1; i + t - 1 < 2 * n; ++i) ans = max(ans, min(get(i , i + t - 1) , get(i - t + 1, i) ) ) ; cout << ans; return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...