제출 #344982

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
344982		kkk	Nice sequence (IZhO18_sequence)	C++14	6 / 100	1 ms	384 KiB

sequence

#include<iostream>
#include<cstring>
#define endl '\n'
using namespace std;
long long a[100003],d[100003],used[5002];

int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    long long n,l,r,i,j,t,m;
    cin>>t;
    for(i=0;i<t;i++)
    {
        cin>>n>>m;
        if(n>m)
        {
            cout<<n-1<<endl;
            if(n-1!=0){
           for(j=1;j<n-1;j++)cout<<j<<" ";cout<<n-1<<endl;}
        }
        else {
            cout<<m-1<<endl;
            if(m-1!=0){
             for(j=1;j<m-1;j++)cout<<-j<<" ";cout<<-m+1<<endl;}
        }

    }

}

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp: In function 'int main()':
sequence.cpp:21:12: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   21 |            for(j=1;j<n-1;j++)cout<<j<<" ";cout<<n-1<<endl;}
      |            ^~~
sequence.cpp:21:43: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   21 |            for(j=1;j<n-1;j++)cout<<j<<" ";cout<<n-1<<endl;}
      |                                           ^~~~
sequence.cpp:26:14: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   26 |              for(j=1;j<m-1;j++)cout<<-j<<" ";cout<<-m+1<<endl;}
      |              ^~~
sequence.cpp:26:46: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   26 |              for(j=1;j<m-1;j++)cout<<-j<<" ";cout<<-m+1<<endl;}
      |                                              ^~~~
sequence.cpp:12:17: warning: unused variable 'l' [-Wunused-variable]
   12 |     long long n,l,r,i,j,t,m;
      |                 ^
sequence.cpp:12:19: warning: unused variable 'r' [-Wunused-variable]
   12 |     long long n,l,r,i,j,t,m;
      |                   ^

• Subtask 1: 6 / 6
• Subtask 2: 0 / 9
• Subtask 3: 0 / 14
• Subtask 4: 0 / 15
• Subtask 5: 0 / 14
• Subtask 6: 0 / 18
• Subtask 7: 0 / 24