이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//
// A.cpp
// torelax
//
// Created by Rakhman on 1/5/21.
//
#include <cstring>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <queue>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <cassert>
#include <iterator>
#define ios ios_base::sync_with_stdio(0), cout.tie(0), cin.tie(0);
#define S second
#define F first
#define pb push_back
#define nl '\n'
#define NL cout << '\n';
#define EX exit(0)
#define all(s) s.begin(), s.end()
#define no_answer {cout << "NO"; exit(0);}
#define FOR(i, start, finish, k) for(llong i = start; i <= finish; i += k)
const long long mxn = 1e6 + 110;
const long long mnn = 1e3 + 2;
const long long mod = 1e9 + 7;
const long long inf = 1e18;
const long long OO = 1e9;
typedef long long llong;
typedef unsigned long long ullong;
using namespace std;
int n, m;
llong b[mxn];
int main() {
cin >> n >> m;
for(int i = 1; i <= n; i++){
cin >> b[i];
}
for(int i = 1; i <= m; i++){
llong l, r, x, mx = 0;
cin >> l >> r >> x;
bool ok = 1;
for(int j = l; j <= r; j++){
if(mx > b[j] && mx + b[j] > x){
ok = 0;
break;
}
mx = max(b[j], mx);
}
if(ok == 1) cout << 1 << nl;
else cout << 0 << nl;
}
}
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