답안 #343713

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
343713 2021-01-04T12:15:57 Z apostoldaniel854 관광지 (IZhO14_shymbulak) C++14
100 / 100
179 ms 25700 KB
#include <bits/stdc++.h>

using namespace std;

#define pb push_back
#define dbg(x) cerr << #x << " " << x << "\n"
using ll = long long;

/**
- we have a single cycle in this graph
- we calculate the maximum depth and its count in every tree spanning from the cycle
- we use a segmentree on a cyclic vector (we will double it)
- now we solve independently for every tree spaning from the cycle
**/

const int MAX_N = 2e5;
vector <int> cycle;
int state[1 + MAX_N];
bool fix[1 + MAX_N];
vector <int> v;
vector <int> gr[1 + MAX_N];

void dfs_cycle (int node, int par) {
    state[node] = 1;
    v.pb (node);
    for (int vec : gr[node])
        if (vec != par) {
            if (state[vec] == 0)
                dfs_cycle (vec, node);
            else if (state[vec] == 1) {
                int idx = ((int) v.size ()) - 1;
                while (idx >= 0 && v[idx] != vec) {
                    cycle.pb (v[idx]);
                    idx--;
                }
                cycle.pb (vec);
            }
        }
    v.pop_back ();
    state[node] = 2;
}


struct Node {
    int value;
    ll cnt;
};

Node max_depth[1 + MAX_N];
Node ans;

Node join (Node l, Node r) {
    Node x;
    x = l;
    if (x.value == r.value)
        x.cnt += r.cnt;
    else if (x.value < r.value)
        x = r;
    return x;
}

void dfs_depth (int node, int par) {
    max_depth[node] = {0, 1};
    for (int son : gr[node])
        if (son != par && not fix[son]) {
            dfs_depth (son, node);
            ans = join (ans, {max_depth[node].value + max_depth[son].value + 1, max_depth[node].cnt * max_depth[son].cnt});
            max_depth[node] = join (max_depth[node], {max_depth[son].value + 1, max_depth[son].cnt});
        }
}
struct LazySegTree {
    vector <Node> seg;
    vector <int> lazy;
    int n;
    LazySegTree (int n) {
        this->n = n;
        seg.resize (1 + 4 * n);
        lazy.resize (1 + 4 * n);
    }
    void push (int node) {
        if (lazy[node]) {
            int left_node = node * 2, right_node = node * 2 + 1;
            seg[left_node].value += lazy[node];
            seg[right_node].value += lazy[node];
            lazy[left_node] += lazy[node];
            lazy[right_node] += lazy[node];
            lazy[node] = 0;
        }
    }
    void build (int node, int lb, int rb, vector <Node> &v) {
        if (lb == rb) {
            seg[node] = {v[lb - 1].value + lb - 1, v[lb - 1].cnt};
            return;
        }
        int mid = (lb + rb) / 2, left_node = node * 2, right_node = node * 2 + 1;
        build (left_node, lb, mid, v);
        build (right_node, mid + 1, rb, v);
        seg[node] = join (seg[left_node], seg[right_node]);
    }
    void update (int node, int lb, int rb, int q_left, int q_right, int to_add) {
        if (q_left <= lb && rb <= q_right) {
            seg[node].value += to_add;
            lazy[node] += to_add;
            return;
        }
        int mid = (lb + rb) / 2, left_node = node * 2, right_node = node * 2 + 1;
        push (node);
        if (q_left <= mid)
            update (left_node, lb, mid, q_left, q_right, to_add);
        if (q_right >= mid + 1)
            update (right_node, mid + 1, rb, q_left, q_right, to_add);
        seg[node] = join (seg[left_node], seg[right_node]);
    }
    Node query (int node, int lb, int rb, int q_left, int q_right) {
        if (q_left > q_right)
            return {0, 0};
        if (q_left <= lb && rb <= q_right)
            return seg[node];
        int mid = (lb + rb) / 2, left_node = node * 2, right_node = node * 2 + 1;
        push (node);
        Node ans = {0, 0};
        if (q_left <= mid)
            ans = join (ans, query (left_node, lb, mid, q_left, q_right));
        if (q_right >= mid + 1)
            ans = join (ans, query (right_node, mid + 1, rb, q_left, q_right));
        return ans;
    }
};

/**
6
1 2
1 3
2 4
4 3
4 5
4 6
**/

int main () {
    ios::sync_with_stdio (false);
    cin.tie (0); cout.tie (0);
    int n;
    cin >> n;
    for (int i = 1; i <= n; i++) {
        int x, y;
        cin >> x >> y;
        gr[x].pb (y);
        gr[y].pb (x);
    }
    dfs_cycle (1, 0);
    for (int x : cycle)
        fix[x] = true;
    for (int x : cycle)
        dfs_depth (x, 0);
    vector <Node> elements;
    for (int x : cycle)
        elements.pb (max_depth[x]);
    for (int x : cycle)
        elements.pb (max_depth[x]);
    int m = cycle.size ();
    int sz = elements.size ();
    LazySegTree helper (sz);
    helper.build (1, 1, sz, elements);
    int from_right = m / 2;
    for (int i = 1; i <= m; i++) {
        Node ans_right = helper.query (1, 1, sz, i + 1, i + from_right);
        Node best = {ans_right.value + elements[i - 1].value, ans_right.cnt * elements[i - 1].cnt};
        ans = join (ans, best);
        helper.update (1, 1, sz, 1, i, 1);
        helper.update (1, 1, sz, i + 1, sz, -1);
    }
    cout << ans.cnt << "\n";
    return 0;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 5100 KB Output is correct
2 Correct 4 ms 5100 KB Output is correct
3 Correct 4 ms 5100 KB Output is correct
4 Correct 4 ms 5100 KB Output is correct
5 Correct 4 ms 5100 KB Output is correct
6 Correct 4 ms 5100 KB Output is correct
7 Correct 4 ms 5100 KB Output is correct
8 Correct 4 ms 5100 KB Output is correct
9 Correct 4 ms 5228 KB Output is correct
10 Correct 4 ms 5100 KB Output is correct
11 Correct 4 ms 5100 KB Output is correct
12 Correct 4 ms 5100 KB Output is correct
13 Correct 4 ms 5100 KB Output is correct
14 Correct 4 ms 5100 KB Output is correct
15 Correct 4 ms 5100 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 5356 KB Output is correct
2 Correct 4 ms 5100 KB Output is correct
3 Correct 4 ms 5228 KB Output is correct
4 Correct 4 ms 5100 KB Output is correct
5 Correct 5 ms 5356 KB Output is correct
6 Correct 5 ms 5356 KB Output is correct
7 Correct 6 ms 5356 KB Output is correct
8 Correct 6 ms 5356 KB Output is correct
9 Correct 6 ms 5356 KB Output is correct
10 Correct 6 ms 5356 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 77 ms 9868 KB Output is correct
2 Correct 81 ms 10348 KB Output is correct
3 Correct 91 ms 25700 KB Output is correct
4 Correct 52 ms 11628 KB Output is correct
5 Correct 46 ms 11500 KB Output is correct
6 Correct 179 ms 15852 KB Output is correct
7 Correct 124 ms 14060 KB Output is correct
8 Correct 94 ms 17260 KB Output is correct
9 Correct 97 ms 17516 KB Output is correct
10 Correct 87 ms 19296 KB Output is correct
11 Correct 101 ms 17376 KB Output is correct
12 Correct 114 ms 17888 KB Output is correct