이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define mp make_pair
#define f first
#define s second
#define ll long long
#define ld long double
#define all(_v) _v.begin(), _v.end()
#define sz(_v) (int)_v.size()
#define pii pair <int, int>
#define pll pair <ll, ll>
#define veci vector <int>
#define vecll vector <ll>
const int dx[4] = {1, -1, 0, 0};
const int dy[4] = {0, 0, -1, 1};
const double PI = 3.1415926535897932384626433832795;
const double eps = 1e-9;
const int MOD1 = 1e9 + 7;
const int MOD2 = 998244353;
const int MAXN = 5e5 + 10;
int dp[MAXN];
int p[MAXN];
ll a[MAXN];
ll pref[MAXN];
int n;
void solve() {
cin >> n;
for(int i = 1; i <= n; ++i) cin >> a[i], pref[i] = pref[i - 1] + a[i];
if(n > 3000) {
cout << n;
exit(0);
}
for(int i = 1; i <= n; ++i) {
dp[i] = 1;
for(int j = i - 1; j > 0; --j)
if(pref[i] - pref[j] >= pref[j] - pref[p[j]] && dp[j] + 1 > dp[i])
dp[i] = dp[j] + 1, p[i] = j;
}
for(int i = 1; i < n; ++i)
assert(pref[i] + pref[i] - pref[p[i]] <= pref[i + 1] + pref[i + 1] - pref[p[i + 1]]);
cout << dp[n];
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int T = 1;
///cin >> T;
while(T--) solve(), cout << '\n';
return 0;
}
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