제출 #343653

#제출 시각아이디문제언어결과실행 시간메모리
343653_aniK개의 묶음 (IZhO14_blocks)C++17
53 / 100
1106 ms135332 KiB
#define BUGO(x) cerr << #x << " = " << (x) << '\n';
#include <iostream>
#include <algorithm>
#include <stack>
using namespace std;
using ll = long long;
ll inf = 1'000'000'000'000'000'000LL;
ll dp[100'002][102], a[100'002];
ll mn[4 * 100'002][102];
struct el {
    ll x; int ind;
};
bool operator<(const el& a, const el& b) {
    return a.x < b.x;
}
void Add(int v, int vl, int vr, int k, int pos) {
    if (vl == vr) {
        mn[v][k] = dp[pos][k];
        return;
    }
    int m = (vl + vr) / 2;
    if (pos <= m)
        Add(v * 2, vl, m, k, pos);
    else Add(v * 2 + 1, m + 1, vr, k, pos);
    mn[v][k] = min(mn[v * 2][k], mn[v * 2 + 1][k]);
}
ll Mn(int v, int vl, int vr, int k, int l, int r) {
    if (vl == l && vr == r) {
        return mn[v][k];
    }
    int m = (vl + vr) / 2;
    ll res = inf;
    if (l <= m) res = min(res, Mn(v * 2, vl, m, k, l, min(r, m)));
    if (r > m) res = min(res, Mn(v * 2 + 1, m + 1, vr, k, max(l, m + 1), r));
    return res;
}
int main()
{
    int n, k;
    cin >> n >> k;
    for (int i = 1; i <= n; i++)
        cin >> a[i];
    for (int i = 0; i <= n; i++)
        for (int curk = 1; curk <= k; curk++)
            dp[i][curk] = inf;

    for (int curk = 1; curk <= k; curk++) {
        stack<el> x;
        x.push({ inf, 0 });
        for (int i = 1; i <= n; i++) {
            while (x.top().x < a[i])x.pop();
            el prev = x.top();
            x.push({ a[i], i });
            if (i < curk) {
                Add(1, 1, n, curk, i);
                continue;
            }
            if (curk == 1)
                dp[i][curk] = ((i - 1 != 0) ? max(dp[i - 1][1], a[i]) : a[i]);
            else if (prev.ind == 0) {
                dp[i][curk] = ((i - 1 == 0) ? 0 : Mn(1, 1, n, curk - 1, 1, i - 1)) + a[i];
            }
            else dp[i][curk] = min(dp[prev.ind][curk], Mn(1, 1, n, curk - 1, prev.ind, i - 1) + a[i]);
            Add(1, 1, n, curk, i);
        }
    }

    /*for (int i = 0; i <= n; i++)
    {
        for (int curk = 0; curk <= k; curk++)
            cerr << dp[i][curk] << ' ';
        cerr << '\n';
    }*/
    cout << dp[n][k] << '\n';
    return 0;
}
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