제출 #342844

#제출 시각아이디문제언어결과실행 시간메모리
342844limabeansSjekira (COCI20_sjekira)C++17
110 / 110
62 ms27904 KiB
#include <bits/stdc++.h> using namespace std; template<typename T> void out(T x) { cout << x << endl; exit(0); } #define watch(x) cout << (#x) << " is " << (x) << endl using ll = long long; const int maxn = 1e6 + 5; int n; ll a[maxn]; vector<int> g[maxn]; int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); cin>>n; for (int i=1; i<=n; i++) { cin>>a[i]; } ll res = 0; for (int i=0; i<n-1; i++) { int u,v; cin>>u>>v; g[u].push_back(v); g[v].push_back(u); res += max(a[u],a[v]); } ll sum = 0; ll hi = 0; for (int i=1; i<=n; i++) { hi = max(hi,a[i]); sum += a[i]; } res += sum; res -= hi; out(res); return 0; } // [1] it's optimal to always snip off an edge from the max node in the tree (swapping argument) // sum over edges e { max(e.u, e.v) } // [2] every node is eventually isolated and snipped off // sum a[i] // subtract max a[i] because it's contribution is entirely from [1]
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