제출 #342764

#제출 시각아이디문제언어결과실행 시간메모리
342764mohamedsobhi777Watching (JOI13_watching)C++14
100 / 100
413 ms16236 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #pragma GCC optimize("-Ofast") //#pragma GCC optimize("trapv") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,sse4.2,popcnt,abm,mmx,avx2,tune=native") #pragma GCC optimize("-ffast-math") #pragma GCC optimize("-funroll-loops") using namespace std; using namespace __gnu_pbds; #define vi vector<int> #define vll vector<ll> #define vii vector<pair<int, int>> #define vvi vector<vi> #define vvii vector<vii> #define pii pair<int, int> #define pll pair<ll, ll> #define loop(_) for (int __ = 0; __ < (_); ++__) #define forn(i, n) for (int i = 0; i < n; ++i) #define pb push_back #define f first #define s second #define sz(_) ((int)_.size()) #define all(_) _.begin(), _.end() #define uni(_) unique(_) #define lb lower_bound #define ub upper_bound #define si set<int> #define ms multiset<int> #define qi queue<int> #define pq prioriry_queue<int> #define mi map<int, int> #define inc(i, l, r) for (int i = l; i <= r; i++) #define dec(i, l, r) for (int i = l; i >= r; i--) using lll = __int128; using ll = long long; using ld = long double; const int N = 2000 + 7; const ll mod = 1e9 + 7; const ll inf = 2e18; auto ra = [] {char *p = new char ; delete p ; return ll(p) ; }; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count() * (ra() | 1)); typedef tree<pii, null_type, less<pii>, rb_tree_tag, tree_order_statistics_node_update> os; __int128 read() { __int128 x = 0, f = 1; char ch = getchar(); while (ch < '0' || ch > '9') { if (ch == '-') f = -1; ch = getchar(); } while (ch >= '0' && ch <= '9') { x = x * 10 + ch - '0'; ch = getchar(); } return x * f; } void print(__int128 x) { if (x < 0) { putchar('-'); x = -x; } if (x > 9) print(x / 10); putchar(x % 10 + '0'); } bool cmp(__int128 x, __int128 y) { return x > y; } int n, p, q; int dp[N][N]; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> n >> p >> q; vi a(n); for (auto &u : a) cin >> u; sort(all(a)); q = min(q, n); p = min(p, max(0, n - q)); vi go(n + 1, 0), go2(n + 1, 0); auto check = [&](int mid) -> bool { int j1 = 0, j2 = 0; inc(i, 0, n - 1) { while (j1 + 1 < n && a[j1 + 1] <= a[i] + mid - 1) ++j1; while (j2 + 1 < n && a[j2 + 1] <= a[i] + mid * 2 - 1) ++j2; go[i] = j1 - i + 1; go2[i] = j2 - i + 1; } inc(i, 0, n) memset(dp[i], 0, sizeof dp[i]); inc(i, 0, p) { inc(j, 0, q) { if (i + 1 <= p) dp[i + 1][j] = max(dp[i + 1][j], dp[i][j] + go[dp[i][j]]); if (j + 1 <= q) dp[i][j + 1] = max(dp[i][j + 1], dp[i][j] + go2[dp[i][j]]); } } inc(i, 0, p) inc(j, 0, q) if (dp[i][j] >= n) return 1; return 0; }; int ans = 1e9, lo = 1, hi = 1e9; while (lo <= hi) { int mid = (lo + hi) >> 1; if (check(mid)) ans = mid, hi = mid - 1; else lo = mid + 1; } cout << ans; return 0; }
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