이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//Challenge: Accepted
#include <iostream>
#include <algorithm>
#include <vector>
#include <utility>
#include <map>
#define ll long long
#define ff first
#define ss second
#define maxn 1000005
using namespace std;
struct segtree{
int seg[4 * maxn];
void modify(int cur, int l, int r, int ind, int val) {
if (r <= l) return;
if (r - l == 1) {
seg[cur] = max(seg[cur], val);
//cout << l << " " << r << " " << val << endl;
return;
}
int mid = (l + r) / 2;
if (ind < mid) modify(cur * 2, l, mid, ind, val);
else modify(cur * 2 + 1, mid, r, ind, val);
seg[cur] = max(seg[cur * 2], seg[cur * 2 + 1]);
}
int query(int cur, int l, int r, int ql, int qr) {
if (r <= l || ql >= r || qr <= l) return 0;
if (ql <= l && qr >= r) return seg[cur];
int mid = (l + r) / 2;
return max(query(cur * 2, l, mid, ql, qr), query(cur * 2 + 1, mid, r, ql, qr));
}
}ans, id;
struct query{
int l = 0, r = 0, k = 0, id = 0;
} que[maxn];
inline bool cmp(query a, query b) {
return a.r < b.r;
}
inline bool cmp2 (pair<int, int> a, pair<int, int> b) {
return a.ss < b.ss;
}
int w[maxn];
vector<int> nums;
pair<int, int> mp[maxn];
bool ret[maxn];
int main() {
ios_base::sync_with_stdio(0);cin.tie(0);
int n, m;
cin >> n >> m;
for (int i = 1;i <= n;i++) {
cin >> w[i];
mp[i] = make_pair(w[i], i);
}
sort(mp + 1, mp + 1 + n);
mp[1].ff = 1;
int cur = 1;
for (int i = 2;i <= n;i++) {
if (w[mp[i].ss] > w[mp[i - 1].ss]) cur++;
mp[i].ff = cur;
}
sort(mp + 1, mp + 1 + n, cmp2);
for (int i = 0;i < m;i++) {
cin >> que[i].l >> que[i].r >> que[i].k;
que[i].id = i;
que[i].r++;
}
sort(que, que + m, cmp);
cur = 1;
for (int i = 0;i < m;i++) {
while (cur < que[i].r) {
int upd = id.query(1, 0, n + 1, mp[cur].ff + 1, n + 1);
ans.modify(1, 0, n + 1, upd, w[upd] + w[cur]);
//cout << cur << " " << upd << " " << w[upd] + w[cur] << "\n";
id.modify(1, 0, n + 1, mp[cur].ff, cur);
//cout << cur << " " << mp[w[cur]] << endl;
cur++;
}
int x = ans.query(1, 0, n + 1, que[i].l, que[i].r);
//cerr << que[i].id << " " << x << endl;
ret[que[i].id] = x <= que[i].k ? 1 : 0;
}
for (int i = 0;i < m;i++) cout << (ret[i] ? 1 : 0) << "\n";
}
/*
5 2
3 5 1 8 2
1 3 6
2 5 3
*/
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