oj.uz

답안 #341875

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
341875 2020-12-31T10:55:41 Z Redhood Intergalactic ship (IZhO19_xorsum) C++14
47 / 100
 2000 ms 3556 KB 
#include<bits/stdc++.h>
#define fi first
#define se second
#define len(x) (int)(x).size()
#define pb push_back
#define p2(x) (x)*(x)
#define all(x) (x).begin() , (x).end()
#define mkp make_pair


//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("-O3")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
typedef long double ld;
typedef long long ll;

//#define int long long
const int BT = 8;
const int mod = (int)1e9 + 7;
const int N = 1001;
const int NN = 1e5 + 10;
int  fact[NN] , pw2[NN] , CHOOSE[NN][2];
int binpow(int a , int b){
    if(b == 0)
        return 1;
    int ans = binpow(a , b >> 1);
    ans = (1ll * ans * ans) % mod;
    if(b & 1)
        ans = (1ll * ans * a) % mod;
    return ans;
}
int INV(int x){
    return binpow(x , mod-2);
}
void md(int &a){
//    a %= mod;
    if(a >= mod)
        a-=mod;
}
void prep(){
    fact[0] = 1;
    for(int i = 1; i < NN; ++i)
        fact[i] = (1ll * fact[i-1] * i) % mod;
    pw2[0] = 1;
    for(int i =1;  i < NN; ++i)
        pw2[i] = (1ll * pw2[i-1] * 2) % mod;
    CHOOSE[0][0] = 1;
    for(int i = 1; i <  NN; ++i){
        CHOOSE[i][0] = (CHOOSE[i-1][0] + CHOOSE[i-1][1]);
        md(CHOOSE[i][0]);
        CHOOSE[i][1] = (CHOOSE[i-1][1] + CHOOSE[i-1][0]);
        md(CHOOSE[i][1]);
    }
}
int Cnk(int n , int k){
    if(k == 0)
        return 1;
    return (1ll * fact[n] * (INV(fact[k]))%mod * INV(fact[n-k])%mod);
}

void brute(vector < int > &a , vector < pair < int , int > > &lines , vector < int > &X){
    int answer = 0;
    int S2 = 0 , Mult = 0;
    for(int msk = 0 ; msk < (1 << len(lines)); ++msk){
        vector < int > nw = a;
        for(int j = 0 ; j < len(lines); ++j){
            if((1 << j) & msk){
                for(int f = lines[j].fi; f <= lines[j].se; ++f)
                    nw[f] ^= X[j];
            }
        }
        for(int f = 0 ; f < len(a); ++f)
            S2 += (f + 1) * (len(a) - f) * nw[f] * nw[f];
        for(int f = 0 ; f < len(a); ++f)
            for(int j = f + 1; j < len(a); ++j)
                Mult +=2 * (f + 1) * (len(a) - j) * nw[f] * nw[j];
        for(int f = 0 ; f < len(a); ++f){
            int cursum = 0;
            for(int z = f; z < len(a); ++z){
                cursum += nw[z] , md(cursum);
                answer += 1ll * cursum * cursum % mod;
                md(answer);
            }
        }
    }
    #ifdef LOCAL
        cout << " BRUTE ";
    #endif // LOCAL
    cout << S2 << ' ' << Mult << ' ';
    cout << answer;

}
signed main()
{
    prep();
    ios_base::sync_with_stdio(0) , cin.tie(0) , cout.tie(0);
    int n;
    cin >> n;
    vector < int > a(n);
    for(auto &i : a)cin >> i;
    int q;
    cin >> q;


    vector < pair < int , int > > lines;
    vector < int > X;
    for(int i = 0 ; i < q; ++i){
        int l , r , x;
        cin >> l >> r >> x;
        --l , --r;
        lines.pb({l , r});
        X.pb(x);
    }

//    brute(a , lines , X);
//    cout << endl;
    int Sin2 = 0;


    int Smult = 0;
    for(int i = 0 ; i < n; ++i){
        for(int j = i; j < n; ++j){

            int fir[BT][2] , sec[BT][2] , nowhere = 0;

            for(int z = 0 ; z < BT; ++z)
                for(int zz = 0; zz < 2; ++zz)
                    fir[z][zz] = sec[z][zz] = 0;

            for(int ind = 0 ; ind < len(lines); ++ind){
                if(lines[ind].fi <= i && lines[ind].se >= j)
                        continue;

                for(int b = 0 ; b < BT; ++b){
                    int bit = ((1 << b) & X[ind]) > 0;
                    if(lines[ind].fi <= i && lines[ind].se >= i)
                        fir[b][bit]++;
                    if(lines[ind].fi <= j && lines[ind].se >= j)
                        sec[b][bit]++;
                }
                int bad = 0;
                if(lines[ind].fi <= i && lines[ind].se >= i)
                    bad += 0;
                else bad += 1;
                if(lines[ind].fi <= j && lines[ind].se >= j)
                    bad += 0;
                else bad += 1;
                if(bad == 2){
                    nowhere++;
                }
            }
            int both[BT][BT][4];


            for(int z = 0 ; z < BT; ++z)
                for(int zz = 0 ; zz < BT; ++zz)
                    for(int zzz = 0; zzz < 4; ++zzz)
                            both[z][zz][zzz]= 0;

            for(int ind = 0 ;  ind < len(lines); ++ind){
                if(lines[ind].fi > i || lines[ind].se < j)
                    continue;
                for(int b1=0;b1<BT;++b1)
                for(int b2=0;b2<BT;++b2){
                    int bit1,bit2;
                    bit1 = ((1 << b1) & X[ind]) > 0;
                    bit2 = ((1 << b2) & X[ind]) > 0;
                    both[b1][b2][(bit1<<1)|bit2]++;
                }
            }



            /// it's dp motherfuckaaa


            for(int B1=0;B1<BT;++B1){
                for(int B2=0;B2<BT;++B2){
                    /// okay
                    /// omg that's strange task
                    /// weird
                    /// lulz okay

                    int dp[2][4];
                    int bt = 0;
                    fill(dp[0], dp[0]+4 , 0);
                    dp[0][0] = 1;
                    for(int msk = 0; msk < 4; ++msk){
                        /// lulz okay
                        bt ^= 1;
                        fill(dp[bt] , dp[bt] + 4 , 0);
                        for(int prvmsk = 0; prvmsk < 4; ++prvmsk){
                            dp[bt][prvmsk] += (1ll * dp[bt^1][prvmsk] * CHOOSE[both[B1][B2][msk]][0]) % mod;
                            md(dp[bt][prvmsk]);
                            dp[bt][prvmsk^msk] += (1ll * dp[bt^1][prvmsk] * CHOOSE[both[B1][B2][msk]][1]) % mod;
                            md(dp[bt][prvmsk^msk]);
                        }
                    }
                    int BIT1 , BIT2;
                    BIT1 = ((1 << B1) & a[i]) > 0;
                    BIT2 = ((1 << B2) & a[j]) > 0;
                    for(int bit1=0;bit1<=1;++bit1){
                        int cur1 = 1ll*pw2[fir[B1][0]]*CHOOSE[fir[B1][1]][bit1^BIT1]%mod;
                        for(int bit2=0;bit2<=1;++bit2){

                            int cur2 = 1ll*pw2[sec[B2][0]]*CHOOSE[sec[B2][1]][bit2^BIT2]%mod;
                            /// and yo
                            /// lul from both we need bit1^1 , bit2^1

                            int that = 1ll*pw2[nowhere]*1ll*(i+1)%mod*(n-j)%mod*cur1%mod*cur2%mod*dp[bt][((bit1^1)<<1)|(bit2^1)]%mod*(1<<B1)%mod*(1<<B2)%mod;
                            if(i == j)
                                Sin2 += that , md(Sin2);
                            else
                                Smult += that , md(Smult);
//                            if(i == 0 && j == 1 && max(B1,B2) < 2){
//                                cout << " BIT'S \n";
//                                cout << B1 << ' ' << bit1 << '\n';
//                                cout << B2 << ' ' << bit2 << '\n';
//
//                                cout << nowhere << '\n';
//                                cout << cur1 << ' ' << cur2 << ' ' << dp[bt][((bit1^1)<<1)|(bit2^1)] << '\n';
//                                cout << " XM " << pw2[sec[B1][0]] << ' ' << CHOOSE[sec[B2][1]][bit2^BIT2] << ' ' << BIT2 << endl;
//                                cout <<  " THAT " << that << endl;
//                            }
                        }
                    }
                }
            }
        }
    }
//    cout << " YO " << Sin2 << endl;
    int answer = (1ll*Sin2 + 1ll*Smult*2)%mod;
    cout << answer;
//    assert(answer != 52);
    return 0;
}
/*
3
1 2 3
3
2 3 1
1 2 4
1 3 7


2
1 2
2
1 2 4
2 2 1



*/

Subtask #1
4.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 1900 KB Output is correct
2 Correct 3 ms 1900 KB Output is correct
3 Correct 4 ms 1900 KB Output is correct
4 Correct 4 ms 1920 KB Output is correct
5 Correct 4 ms 1900 KB Output is correct

Subtask #2
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 1900 KB Output is correct
2 Correct 3 ms 1900 KB Output is correct
3 Correct 4 ms 1900 KB Output is correct
4 Correct 4 ms 1920 KB Output is correct
5 Correct 4 ms 1900 KB Output is correct
6 Correct 70 ms 1900 KB Output is correct
7 Correct 70 ms 1900 KB Output is correct
8 Correct 71 ms 1900 KB Output is correct

Subtask #3
0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 2080 ms 3556 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #4
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 2083 ms 1900 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #5
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 11 ms 1900 KB Output is correct
2 Correct 10 ms 1900 KB Output is correct
3 Correct 9 ms 1900 KB Output is correct

Subtask #6
11.0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 11 ms 1900 KB Output is correct
2 Correct 10 ms 1900 KB Output is correct
3 Correct 9 ms 1900 KB Output is correct
4 Correct 124 ms 2028 KB Output is correct
5 Correct 124 ms 2028 KB Output is correct
6 Correct 123 ms 2156 KB Output is correct
7 Correct 124 ms 2028 KB Output is correct

Subtask #7
19.0 / 19.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 1900 KB Output is correct
2 Correct 3 ms 1900 KB Output is correct
3 Correct 4 ms 1900 KB Output is correct
4 Correct 4 ms 1920 KB Output is correct
5 Correct 4 ms 1900 KB Output is correct
6 Correct 70 ms 1900 KB Output is correct
7 Correct 70 ms 1900 KB Output is correct
8 Correct 71 ms 1900 KB Output is correct
9 Correct 11 ms 1900 KB Output is correct
10 Correct 10 ms 1900 KB Output is correct
11 Correct 9 ms 1900 KB Output is correct
12 Correct 135 ms 2028 KB Output is correct
13 Correct 138 ms 2096 KB Output is correct
14 Correct 101 ms 2028 KB Output is correct
15 Correct 136 ms 1900 KB Output is correct

Subtask #8
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 1900 KB Output is correct
2 Correct 3 ms 1900 KB Output is correct
3 Correct 4 ms 1900 KB Output is correct
4 Correct 4 ms 1920 KB Output is correct
5 Correct 4 ms 1900 KB Output is correct
6 Correct 70 ms 1900 KB Output is correct
7 Correct 70 ms 1900 KB Output is correct
8 Correct 71 ms 1900 KB Output is correct
9 Correct 11 ms 1900 KB Output is correct
10 Correct 10 ms 1900 KB Output is correct
11 Correct 9 ms 1900 KB Output is correct
12 Correct 124 ms 2028 KB Output is correct
13 Correct 124 ms 2028 KB Output is correct
14 Correct 123 ms 2156 KB Output is correct
15 Correct 124 ms 2028 KB Output is correct
16 Correct 135 ms 2028 KB Output is correct
17 Correct 138 ms 2096 KB Output is correct
18 Correct 101 ms 2028 KB Output is correct
19 Correct 136 ms 1900 KB Output is correct
20 Execution timed out 2084 ms 3556 KB Time limit exceeded
21 Halted 0 ms 0 KB -

Subtask #9
0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 1900 KB Output is correct
2 Correct 3 ms 1900 KB Output is correct
3 Correct 4 ms 1900 KB Output is correct
4 Correct 4 ms 1920 KB Output is correct
5 Correct 4 ms 1900 KB Output is correct
6 Correct 70 ms 1900 KB Output is correct
7 Correct 70 ms 1900 KB Output is correct
8 Correct 71 ms 1900 KB Output is correct
9 Execution timed out 2080 ms 3556 KB Time limit exceeded
10 Halted 0 ms 0 KB -