oj.uz

답안 #341868

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
341868 2020-12-31T10:35:36 Z AmineWeslati 삶의 질 (IOI10_quality) C++14
80 / 100
 5000 ms 210692 KB 
//Never stop trying
/*#pragma GCC target ("avx2")
#pragma GCC optimize ("Ofast")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")*/
#include "bits/stdc++.h"
using namespace std;
#define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)

typedef long long ll;
typedef string str;
typedef double db;
typedef long double ld;
typedef pair<int, int> pi;
#define fi first
#define se second
typedef vector<int> vi;
typedef vector<pi> vpi;
typedef vector<str> vs;
typedef vector<ld> vd;
#define pb push_back
#define eb emplace_back
#define sz(x) (int)x.size()
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
#define endl "\n"

#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)

const int MOD = 1e9 + 7; //998244353
const ll INF = 1e18;
const int MX = 3000 + 10;
const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up

template<class T> using V = vector<T>;
template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }

ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up
//constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x))

mt19937 rng(chrono::system_clock::now().time_since_epoch().count());
//mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count());

ll random(ll a, ll b){
    return a + rng() % (b - a + 1);
}

#ifndef LOCAL  
#define cerr if(false) cerr
#endif
#define dbg(x) cerr << #x << " : " << x << endl; 
#define dbgs(x,y) cerr << #x << " : " << x << " / " << #y << " : " << y << endl;
#define dbgv(v) cerr << #v << " : " << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl;
#define here() cerr << "here" << endl;

void IO() {
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#endif
}
#ifndef LOCAL
#include "quality.h"
#endif

int R,C,H,W,g[MX][MX];
vi bit;

void upd(int i, int v){
	for(;i<sz(bit); i+=i&-i) bit[i]+=v;
}
int get(int i){
	int ans=0;
	for(;i;i-=i&-i) ans+=bit[i];
	return ans;
}

bool check(int X){
	int cnt[R][C]; memset(cnt,0,sizeof(cnt));
	bit.assign(R*C+1,0);

	FOR(i,0,R){
		FOR(j,0,C){
			upd(g[i][j],1);
			cnt[i][j]=get(X);
			if(j>=W-1) upd(g[i][j-W+1],-1);
			if(j==C-1) FOR(jj,j-W+2,C) upd(g[i][jj],-1);
		}
	}


	//FOR(i,0,R) FOR(j,0,C) cout << cnt[i][j] << " \n"[j==C-1];
	FOR(i,0,R) FOR(j,0,C){
		if(i) cnt[i][j]+=cnt[i-1][j];
	}
	//FOR(i,0,R) FOR(j,0,C) cout << cnt[i][j] << " \n"[j==C-1];

	FOR(i,H-1,R) FOR(j,W-1,C){
		int val=cnt[i][j];
		if(i-H>=0) val-=cnt[i-H][j];

		if(val>=(H*W+1)/2) return true;
	}
	return false;
}

int rectangle(int rr, int c, int h, int w, int Q[3001][3001]) {
	R=rr,C=c,H=h,W=w; 
	FOR(i,0,R) FOR(j,0,C) g[i][j]=Q[i][j];

	int l=1,r=R*C;
	int ans;
	while(l<=r){
		int X=(l+r)/2;
		if(check(X)){
			ans=X; r=X-1;
		}
		else l=X+1;
	}
	return ans;
}

/*
5 5 3 3
5 11 12 16 25
17 18 2 7 10
4 23 20 3 1
24 21 19 14 9
6 22 8 13 15
*/

/*
2 6 1 5
6 1 2 11 7 5
9 3 4 10 12 8
*/

#ifdef LOCAL
int gg[3001][3001]; 
int main() {
    boost; IO();

    int R,C,H,W; cin>>R>>C>>H>>W;
    FOR(i,0,R) FOR(j,0,C) cin>>gg[i][j];
    cout << rectangle(R,C,H,W,gg) << endl;
    

    return 0;
}
#endif

/* Careful!!!
    .Array bounds
    .Infinite loops
    .Uninitialized variables / empty containers
    .Multisets are shit

   Some insights:
    .Binary search
    .Graph representation
    .Write brute force code
    .Change your approach
*/

Compilation message

quality.cpp: In function 'int rectangle(int, int, int, int, int (*)[3001])':
quality.cpp:122:9: warning: 'ans' may be used uninitialized in this function [-Wmaybe-uninitialized]
  122 |  return ans;
      |         ^~~

Subtask #1
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 620 KB Output is correct
2 Correct 1 ms 620 KB Output is correct
3 Correct 1 ms 620 KB Output is correct

Subtask #2
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 620 KB Output is correct
2 Correct 1 ms 620 KB Output is correct
3 Correct 1 ms 620 KB Output is correct
4 Correct 9 ms 1280 KB Output is correct
5 Correct 8 ms 1280 KB Output is correct
6 Correct 9 ms 1260 KB Output is correct

Subtask #3
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 620 KB Output is correct
2 Correct 1 ms 620 KB Output is correct
3 Correct 1 ms 620 KB Output is correct
4 Correct 9 ms 1280 KB Output is correct
5 Correct 8 ms 1280 KB Output is correct
6 Correct 9 ms 1260 KB Output is correct
7 Correct 99 ms 4076 KB Output is correct
8 Correct 112 ms 4716 KB Output is correct
9 Correct 84 ms 4588 KB Output is correct

Subtask #4
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 620 KB Output is correct
2 Correct 1 ms 620 KB Output is correct
3 Correct 1 ms 620 KB Output is correct
4 Correct 9 ms 1280 KB Output is correct
5 Correct 8 ms 1280 KB Output is correct
6 Correct 9 ms 1260 KB Output is correct
7 Correct 99 ms 4076 KB Output is correct
8 Correct 112 ms 4716 KB Output is correct
9 Correct 84 ms 4588 KB Output is correct
10 Correct 1978 ms 30828 KB Output is correct
11 Correct 1963 ms 30828 KB Output is correct
12 Correct 797 ms 19564 KB Output is correct

Subtask #5
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 620 KB Output is correct
2 Correct 1 ms 620 KB Output is correct
3 Correct 1 ms 620 KB Output is correct
4 Correct 9 ms 1280 KB Output is correct
5 Correct 8 ms 1280 KB Output is correct
6 Correct 9 ms 1260 KB Output is correct
7 Correct 99 ms 4076 KB Output is correct
8 Correct 112 ms 4716 KB Output is correct
9 Correct 84 ms 4588 KB Output is correct
10 Correct 1978 ms 30828 KB Output is correct
11 Correct 1963 ms 30828 KB Output is correct
12 Correct 797 ms 19564 KB Output is correct
13 Execution timed out 5065 ms 210692 KB Time limit exceeded
14 Halted 0 ms 0 KB -