답안 #341862

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
341862 2020-12-31T09:51:27 Z Redhood Intergalactic ship (IZhO19_xorsum) C++14
0 / 100
2000 ms 3808 KB
#include<bits/stdc++.h>
#define fi first
#define se second
#define len(x) (int)(x).size()
#define pb push_back
#define p2(x) (x)*(x)
#define all(x) (x).begin() , (x).end()
#define mkp make_pair


//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("-O3")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
typedef long double ld;
typedef long long ll;

#define int long long
const int mod = (int)1e9 + 7;
const int N = 1001;
const int NN = 1e3 + 10;
int cnt[N][7][2] , fact[NN] , pw2[NN] , CHOOSE[NN][2];
int binpow(int a , int b){
    if(b == 0)
        return 1;
    int ans = binpow(a , b >> 1);
    ans = (1ll * ans * ans) % mod;
    if(b & 1)
        ans = (1ll * ans * a) % mod;
    return ans;
}
int INV(int x){
    return binpow(x , mod-2);
}
void md(int &a){
    if(a >= mod)
        a-=mod;
}
void prep(){
    fact[0] = 1;
    for(int i = 1; i < NN; ++i)
        fact[i] = (1ll * fact[i-1] * i) % mod;
    pw2[0] = 1;
    for(int i =1;  i < NN; ++i)
        pw2[i] = (1ll * pw2[i-1] * 2) % mod;
    CHOOSE[0][0] = 1;
    for(int i = 1; i <  NN; ++i){
        CHOOSE[i][0] = (CHOOSE[i-1][0] + CHOOSE[i-1][1]);
        md(CHOOSE[i][0]);
        CHOOSE[i][1] = (CHOOSE[i-1][1] + CHOOSE[i-1][0]);
        md(CHOOSE[i][1]);
    }
}
int Cnk(int n , int k){
    if(k == 0)
        return 1;
    return (1ll * fact[n] * (INV(fact[k]))%mod * INV(fact[n-k])%mod);
}
signed main()
{
    prep();
    ios_base::sync_with_stdio(0) , cin.tie(0) , cout.tie(0);
    int n;
    cin >> n;
    vector < int > a(n);
    for(auto &i : a)cin >> i;
    int q;
    cin >> q;


    vector < pair < int , int > > lines;
    vector < int > X;
    for(int i = 0 ; i < q; ++i){
        int l , r , x;
        cin >> l >> r >> x;
        --l , --r;
        lines.pb({l , r});
        X.pb(x);
    }
    int Sin2 = 0;


    int Smult = 0;
    for(int i = 0 ; i < n; ++i){
        for(int j = i; j < n; ++j){

            int fir[7][2] , sec[7][2] , nowhere = 0;

            for(int z = 0 ; z < 7; ++z)
                for(int zz = 0; zz < 7; ++zz)
                    fir[z][zz] = sec[z][zz] = 0;
            for(int ind = 0 ; ind < len(lines); ++ind){
                if(lines[ind].fi <= i && lines[ind].se >= j)
                        continue;

                for(int b = 0 ; b < 7; ++b){
                    int bit = ((1 << b) & X[ind]) > 0;
                    if(lines[ind].fi <= i && lines[ind].se >= i)
                        fir[b][bit]++;
                    if(lines[ind].fi <= j && lines[ind].se >= j)
                        sec[b][bit]++;
                }
                int bad = 0;
                if(lines[ind].fi <= i && lines[ind].se >= i)
                    bad += 0;
                else bad += 1;
                if(lines[ind].fi <= j && lines[ind].se >= j)
                    bad += 0;
                else bad += 1;
                if(bad == 2){
                    nowhere++;
                }
            }
            int both[7][7][4];


            for(int z = 0 ; z < 7; ++z)
                for(int zz = 0 ; zz < 7; ++zz)
                    for(int zzz = 0; zzz < 4; ++zzz)
                            both[z][zz][zzz]= 0;

            for(int ind = 0 ;  ind < len(lines); ++ind){
                if(lines[ind].fi > i || lines[ind].se < j)
                    continue;
                for(int b1=0;b1<7;++b1)
                for(int b2=0;b2<7;++b2){
                    int bit1,bit2;
                    bit1 = ((1 << b1) & X[ind]) > 0;
                    bit2 = ((1 << b2) & X[ind]) > 0;
                    both[b1][b2][(bit1<<1)|bit2]++;
                }
            }



            /// it's dp motherfuckaaa


            for(int B1=0;B1<7;++B1){
                for(int B2=0;B2<7;++B2){
                    /// okay
                    /// omg that's strange task
                    /// weird
                    /// lulz okay

                    int dp[2][4];
                    int bt = 0;
                    fill(dp[0], dp[0]+4 , 0);
                    dp[0][0] = 1;
                    for(int msk = 0; msk < 4; ++msk){
                        /// lulz okay
                        bt ^= 1;
                        fill(dp[bt] , dp[bt] + 4 , 0);
                        for(int prvmsk = 0; prvmsk < 4; ++prvmsk){
                            dp[bt][prvmsk] += (1ll * dp[bt^1][prvmsk] * CHOOSE[both[B1][B2][msk]][0]) % mod;
                            md(dp[bt][prvmsk]);
                            dp[bt][prvmsk^msk] += (1ll * dp[bt^1][prvmsk] * CHOOSE[both[B1][B2][msk]][1]) % mod;
                            md(dp[bt][prvmsk^msk]);
                        }
                    }
                    int BIT1 , BIT2;
                    BIT1 = ((1 << B1) & a[i]) > 0;
                    BIT2 = ((1 << B2) & a[j]) > 0;
                    for(int bit1=0;bit1<=1;++bit1){
                        int cur1 = pw2[fir[B1][0]]*CHOOSE[fir[B1][1]][bit1^BIT1];
                        for(int bit2=0;bit2<=1;++bit2){

                            int cur2 = pw2[sec[B1][0]]*CHOOSE[sec[B2][1]][bit2^BIT2];
                            /// and yo
                            /// lul from both we need bit1^1 , bit2^1

                            int that = 1ll*pw2[nowhere]*1ll*(i+1)%mod*(n-j)%mod*cur1%mod*cur2%mod*dp[bt][((bit1^1)<<1)|(bit2^1)]%mod*(1<<B1)%mod*(1<<B2)%mod;
                            if(i == j)
                                Sin2 += that , md(Sin2);
                            else
                                Smult += that , md(Smult);
                        }
                    }
                }
            }
        }
    }
//    cout << " YO " << Sin2 << endl;
    int answer = (1ll*Sin2 + 1ll*Smult*2)%mod;
    cout << answer;
    return 0;
}
/*


*/

Compilation message

xorsum.cpp: In function 'int main()':
xorsum.cpp:92:45: warning: iteration 2 invokes undefined behavior [-Waggressive-loop-optimizations]
   92 |                     fir[z][zz] = sec[z][zz] = 0;
      |                                  ~~~~~~~~~~~^~~
xorsum.cpp:91:36: note: within this loop
   91 |                 for(int zz = 0; zz < 7; ++zz)
      |                                 ~~~^~~
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Incorrect 1 ms 364 KB Output isn't correct
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Incorrect 1 ms 364 KB Output isn't correct
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 2084 ms 3808 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 2084 ms 364 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 5 ms 364 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 5 ms 364 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Incorrect 1 ms 364 KB Output isn't correct
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Incorrect 1 ms 364 KB Output isn't correct
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Incorrect 1 ms 364 KB Output isn't correct
4 Halted 0 ms 0 KB -