Submission #340001

#TimeUsernameProblemLanguageResultExecution timeMemory
340001amunduzbaevLuxury burrow (IZhO13_burrow)C++14
0 / 100
5 ms4332 KiB
/** made by amunduzbaev **/ #include <bits/stdc++.h> //~ #include <ext/pb_ds/assoc_container.hpp> //~ #include <ext/pb_ds/tree_policy.hpp> //~ #include <ext/rope> //~ using namespace __gnu_pbds; //~ using namespace __gnu_cxx; using namespace std; #define ff first #define ss second #define pb push_back #define mp make_pair #define ub upper_bound #define lb lower_bound #define ll long long #define ld long double #define pii pair<int, int> #define pll pair<ll, ll> #define sz(x) (int)x.size() #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(),x.rend() #define fastios ios::sync_with_stdio(0);cin.tie(0);cout.tie(0); #define vll vector<ll> #define vii vector<int> #define vpii vector<pii> #define vpll vector<pll> #define cnt(a)__builtin_popcount(a) template<class T> bool umin(T& a, const T& b) {return a > b? a = b, true:false;} template<class T> bool umax(T& a, const T& b) {return a < b? a = b, true:false;} //~ typedef tree<pii,null_type,less<pii>,rb_tree_tag,tree_order_statistics_node_update> ordered_set; const int N = 1e3+5; const int mod = 1e9+7; const ll inf = 1e18; const ld Pi = acos(-1); int s, n, m, k, t, a[N][N]; int tmp[N][N]; int check(int mx){ memset(tmp, 0, sizeof tmp); for(int i=0;i<n;i++){ for(int j=0;j<m;j++){ if(a[i][j] >= mx) tmp[i][j] = 1; } } for(int i=0;i<n;i++){ for(int j=0;j<m;j++){ if(tmp[i][j] && i) tmp[i][j] += tmp[i-1][j]; } } int ans = 0; for(int i=0;i<n;i++){ stack<pii> ss; vii l(m), r(m); for(int j=0;j<m;j++){ if(tmp[i][j] == 0){ while(!ss.empty()) ss.pop(); continue; } while(!ss.empty() && ss.top().ff > tmp[i][j]) ss.pop(); if(!ss.empty()) l[j] = j - ss.top().ss+1; else l[j] = 1; if(!ss.empty() && ss.top().ff == tmp[i][j]) continue; ss.push({tmp[i][j], j}); } while(!ss.empty()) ss.pop(); for(int j=m-1;j>=0;j--){ if(tmp[i][j] == 0){ while(!ss.empty()) ss.pop(); continue; } while(!ss.empty() && ss.top().ff > tmp[i][j]) ss.pop(); if(!ss.empty()) r[j] = ss.top().ss - j+1; else r[j] = 1; if(!ss.empty() && ss.top().ff == tmp[i][j]) continue; ss.push({tmp[i][j], j}); } for(int j=0;j<m;j++) umax(ans, (r[j] + l[j] -1)*tmp[i][j]); } return ans; } void solve(){ cin>>n>>m>>k; set<int> tmp; for(int i=0;i<n;i++){ for(int j=0;j<m;j++){ cin>>a[i][j]; tmp.insert(a[i][j]); } } vii tt; for(auto x:tmp) tt.pb(x); int l = 0, r = sz(tt)-1; while(l+1 < r){ // cout<<l<<" "<<r<<endl; int m = (l + r) >>1; if(check(tt[m]) >= k) l = m; else r = m-1; } if(check(tt[r]) >= k) cout<<tt[r]<<" "<<check(tt[r]); else cout<<tt[l]<<" "<<check(tt[l]); return; } int main(){ fastios int t = 1; if(t) solve(); else { cin>>t; while (t--) solve(); } return 0; }
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