Submission #339959

#	Time	Username	Problem	Language	Result	Execution time	Memory
339959		amunduzbaev	Luxury burrow (IZhO13_burrow)	C++14	0 / 100	2045 ms	27612 KiB

burrow

/** made by amunduzbaev **/
 
#include <bits/stdc++.h>
//~ #include <ext/pb_ds/assoc_container.hpp> 
//~ #include <ext/pb_ds/tree_policy.hpp> 
//~ #include <ext/rope>
 
//~ using namespace __gnu_pbds;
//~ using namespace __gnu_cxx;
using namespace std;
 
#define ff first
#define ss second
#define pb push_back
#define mp make_pair
#define ub upper_bound
#define lb lower_bound
#define ll long long
#define ld long double
#define pii pair<int, int>
#define pll pair<ll, ll>
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(),x.rend()
#define fastios ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define vll vector<ll>
#define vii vector<int>
#define vpii vector<pii>
#define vpll vector<pll>
#define cnt(a)__builtin_popcount(a)
template<class T> bool umin(T& a, const T& b) {return a > b? a = b, true:false;}
template<class T> bool umax(T& a, const T& b) {return a < b? a = b, true:false;}
 
//~ typedef tree<pii,null_type,less<pii>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
 
const int N = 1e3+5;
const int mod = 1e9+7;
const ll inf = 1e18;
const ld Pi = acos(-1);
int s, n, m, k, t, a[N][N];
int tmp[N][N];
int check(int mx){
	memset(tmp, 0, sizeof tmp);
	for(int i=0;i<n;i++){
		for(int j=0;j<m;j++){
			if(a[i][j] >= mx) tmp[i][j] = 1;
		}
	}
	
	for(int i=0;i<n;i++){
		for(int j=0;j<m;j++){
			if(tmp[i][j] && i) tmp[i][j] += tmp[i-1][j];
		}
	}
	int ans = 0;
	for(int i=0;i<n;i++){
		for(int j=0;j<m;j++){
			int cur = mod;
			for(int l=j;l>=0;l--){
				umin(cur, tmp[i][l]);
				umax(ans, cur * (j-l+1));
			}
		}
	}
	return ans;
}

void solve(){
	cin>>n>>m>>k;
	set<int> tmp;
	for(int i=0;i<n;i++){
		for(int j=0;j<m;j++){
			cin>>a[i][j];
			tmp.insert(a[i][j]);
		}
	}
	vii tt;
	for(auto x:tmp) tt.pb(x);
	int l = 0, r = sz(tt)-1;
	while(l+1 < r){
	//	cout<<l<<" "<<r<<endl;
		int m = (l + r) >>1;
		if(check(tt[m]) >= k) l = m;
		else r = m-1;
	}
	if(check(tt[r]) >= k) cout<<tt[r]<<" "<<check(tt[r]);
	else cout<<tt[l]<<" "<<check(tt[l]);
	return;
}
 
int main(){
	fastios
	int t = 1;
	if(t) solve();
	else {
		cin>>t;
		while (t--) solve();
	}
	return 0;
}

• Subtask 1: 0 / 100