oj.uz

답안 #339290

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
339290 2020-12-25T03:21:31 Z 12tqian Kitchen (BOI19_kitchen) C++17
100 / 100
 262 ms 8556 KB 
#pragma comment(linker, "/stack:200000000")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

const double PI = 4 * atan(1);

#define sz(x) (int)(x).size()
#define ll long long
#define ld long double
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define pii pair <int, int>
#define vi vector<int>
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
#define vpi vector<pair<int, int>>
#define vpd vector<pair<double, double>>
#define pd pair<double, double>

#define f0r(i,a) for(int i=0;i<a;i++)
#define f1r(i,a,b) for(int i=a;i<b;i++)
#define trav(a, x) for (auto& a : x)

template<typename A, typename B> ostream& operator<<(ostream &cout, pair<A, B> const &p) { return cout << "(" << p.f << ", " << p.s << ")"; }
template<typename A> ostream& operator<<(ostream &cout, vector<A> const &v) {
  cout << "["; for(int i = 0; i < v.size(); i++) {if (i) cout << ", "; cout << v[i];} return cout << "]";
}

void fast_io(){
    ios_base::sync_with_stdio(0);
    cin.tie(NULL);
    cout.tie(NULL);
}
void io(string taskname){
    string fin = taskname + ".in";
    string fout = taskname + ".out";
    const char* FIN = fin.c_str();
    const char* FOUT = fout.c_str();
    freopen(FIN, "r", stdin);
   // freopen(FOUT, "w", stdout);
    fast_io();
}
const int MAX = 3e2 + 5;
vi v1;
vi v2;
int get1[MAX*MAX];
int get2[MAX*MAX];


set<int> t[MAX*MAX];
int main(){
    fast_io();
  //  io("test");
    int n, m, k;
    cin >> n >> m >> k;
   // cout << n << " " << " " << m << " " << k << endl;
    int sum = 0;
    bool ok = false;
    f0r(i, n){
        int ai;
        cin >> ai;
        sum += ai;
        if(ai<k){
            ok = true;
        }//cout << i << endl;
    }
    //return 0;

    if(sum>= MAX*MAX){
        cout << "Impossible" << endl;
        return 0;
    }
    int bound = n*k;
//    cout << "here" << endl;
    f0r(i, m){
        int bi;
        cin >> bi;
        if(bi<=n){
            v1.eb(bi);
        }
        else v2.eb(bi);
    }
    //return 0;
    if(ok){
        cout << "Impossible" << endl;
        return 0;
    }
    sort(all(v1));
    sort(all(v2));
    vi pos;
    pos.eb(0);
    get1[0] = 1;
    f0r(i, sz(v1)){
        vi tmp;
        for(int x: pos){
            int nxt = v1[i] + x;
            if(get1[nxt] == 0){
                tmp.eb(nxt);
            }
        }
        for(int x: tmp){
            pos.eb(x);
            get1[x] = 1;
        }
    }
    pos.clear();
    pos.eb(0);
    f0r(i, MAX*MAX) get2[i] = -1;
    get2[0] = 0;
    f0r(i, sz(v2)){
        vi tmp;
        for(int x: pos){
            int nxt = v2[i] + x;
            if(get2[nxt] == -1){
                tmp.eb(nxt);
            }
        }
        for(int x: pos){
            int nxt = v2[i] + x;
            get2[nxt] = max(get2[nxt], 1 + get2[x]);
            //if(nxt == 356) cout << get2[nxt]<< " here" << endl;
        }
        for(int x: tmp){
            pos.eb(x);
        }
    }
 //   cout << pos << endl;
    f0r(i, MAX*MAX){
        if(get2[i] == -1) continue;
      //  cout << i << " asdf " << get2[i] << endl;
        t[get2[i]].insert(i);
    }
    int ans = MAX*MAX;
    f0r(i, MAX*MAX){
        if(get1[i] == 0) continue;
        int need = ceil(((double)(bound - i))/n);
        if(i>= sum && i >= bound){
              //  cout << "here" << endl;
           // cout << i << " adsf" <<  endl;
            ans = min(ans, i);
            continue;
        }
      //  cout << need << endl;
     //   cout << need << endl;
        f1r(j, max(need, 0), MAX){
            if(sz(t[j]) == 0) continue;
            int left = sum - i;
        //    cout << "here" << " " << sz(t[j]) << endl;
            auto it = t[j].lb(left);
          //  cout << sz(t[j]) << endl;
          //  cout << left << " lb" << endl;
            if(it != t[j].end()){
               // cout << i <<" asdf" <<  endl;
                ans = min(ans, i  +(*it));
            }
        }
    }
    if(ans == MAX*MAX) {
        cout << "Impossible" << endl;
        return 0;
    }
    cout << ans - sum<< endl;
    return 0;
}

Compilation message

kitchen.cpp:1: warning: ignoring #pragma comment  [-Wunknown-pragmas]
    1 | #pragma comment(linker, "/stack:200000000")
      | 
kitchen.cpp: In function 'void io(std::string)':
kitchen.cpp:51:17: warning: unused variable 'FOUT' [-Wunused-variable]
   51 |     const char* FOUT = fout.c_str();
      |                 ^~~~
kitchen.cpp:52:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   52 |     freopen(FIN, "r", stdin);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~

Subtask #1
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 5100 KB Output is correct
2 Correct 4 ms 5100 KB Output is correct
3 Correct 4 ms 5100 KB Output is correct
4 Correct 4 ms 5100 KB Output is correct
5 Correct 4 ms 5100 KB Output is correct
6 Correct 3 ms 4716 KB Output is correct
7 Correct 3 ms 4716 KB Output is correct
8 Correct 4 ms 5100 KB Output is correct

Subtask #2
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 5100 KB Output is correct
2 Correct 4 ms 5100 KB Output is correct
3 Correct 4 ms 5100 KB Output is correct
4 Correct 4 ms 5100 KB Output is correct
5 Correct 4 ms 5100 KB Output is correct
6 Correct 3 ms 4716 KB Output is correct
7 Correct 3 ms 4716 KB Output is correct
8 Correct 4 ms 5100 KB Output is correct
9 Correct 5 ms 5228 KB Output is correct
10 Correct 4 ms 5100 KB Output is correct
11 Correct 4 ms 5100 KB Output is correct
12 Correct 4 ms 5100 KB Output is correct
13 Correct 5 ms 5100 KB Output is correct

Subtask #3
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 14 ms 5760 KB Output is correct
2 Correct 20 ms 5616 KB Output is correct
3 Correct 28 ms 5632 KB Output is correct
4 Correct 262 ms 6640 KB Output is correct
5 Correct 42 ms 5864 KB Output is correct
6 Correct 14 ms 5484 KB Output is correct

Subtask #4
21.0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 5100 KB Output is correct
2 Correct 4 ms 5100 KB Output is correct
3 Correct 4 ms 5100 KB Output is correct
4 Correct 5 ms 5100 KB Output is correct
5 Correct 4 ms 4716 KB Output is correct

Subtask #5
28.0 / 28.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 5100 KB Output is correct
2 Correct 4 ms 5100 KB Output is correct
3 Correct 4 ms 5100 KB Output is correct
4 Correct 4 ms 5100 KB Output is correct
5 Correct 4 ms 5100 KB Output is correct
6 Correct 3 ms 4716 KB Output is correct
7 Correct 3 ms 4716 KB Output is correct
8 Correct 4 ms 5100 KB Output is correct
9 Correct 5 ms 5228 KB Output is correct
10 Correct 4 ms 5100 KB Output is correct
11 Correct 4 ms 5100 KB Output is correct
12 Correct 4 ms 5100 KB Output is correct
13 Correct 5 ms 5100 KB Output is correct
14 Correct 14 ms 5760 KB Output is correct
15 Correct 20 ms 5616 KB Output is correct
16 Correct 28 ms 5632 KB Output is correct
17 Correct 262 ms 6640 KB Output is correct
18 Correct 42 ms 5864 KB Output is correct
19 Correct 14 ms 5484 KB Output is correct
20 Correct 4 ms 5100 KB Output is correct
21 Correct 4 ms 5100 KB Output is correct
22 Correct 4 ms 5100 KB Output is correct
23 Correct 5 ms 5100 KB Output is correct
24 Correct 4 ms 4716 KB Output is correct
25 Correct 6 ms 5356 KB Output is correct
26 Correct 6 ms 5356 KB Output is correct
27 Correct 13 ms 6124 KB Output is correct
28 Correct 74 ms 6764 KB Output is correct
29 Correct 56 ms 8556 KB Output is correct
30 Correct 31 ms 7148 KB Output is correct