제출 #339286

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
339286		12tqian	Paths (BOI18_paths)	C++17	100 / 100	893 ms	36180 KiB

paths

#pragma comment(linker, "/stack:200000000")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

const double PI = 4 * atan(1);

#define sz(x) (int)(x).size()
#define ll long long
#define ld long double
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define pii pair <int, int>
#define vi vector<int>
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
#define vpi vector<pair<int, int>>
#define vpd vector<pair<double, double>>
#define pd pair<double, double>

#define f0r(i,a) for(int i=0;i<a;i++)
#define f1r(i,a,b) for(int i=a;i<b;i++)
#define trav(a, x) for (auto& a : x)

template<typename A, typename B> ostream& operator<<(ostream &cout, pair<A, B> const &p) { return cout << "(" << p.f << ", " << p.s << ")"; }
template<typename A> ostream& operator<<(ostream &cout, vector<A> const &v) {
  cout << "["; for(int i = 0; i < v.size(); i++) {if (i) cout << ", "; cout << v[i];} return cout << "]";
}

void fast_io(){
    ios_base::sync_with_stdio(0);
    cin.tie(NULL);
    cout.tie(NULL);
}
void io(string taskname){
    string fin = taskname + ".in";
    string fout = taskname + ".out";
    const char* FIN = fin.c_str();
    const char* FOUT = fout.c_str();
    freopen(FIN, "r", stdin);
    freopen(FOUT, "w", stdout);
    fast_io();
}
const int MAX = 3e5 + 5;
vi adj[MAX];
ll num[MAX][5];
vpi edges;
int co[MAX];
ll res[6];
ll cnt[5][5];
vector<vi> states;
int main(){
    fast_io();
    int n, m, k;
    cin >> n >> m >> k;
    f0r(i,n) cin >> co[i];
    f0r(i, n) co[i]--;

    f0r(i, m){
        int u, v;
        cin >> u >> v;
        u--;
        v--;
        adj[u].eb(v);
        adj[v].eb(u);
        edges.eb(mp(min(u, v), max(u, v)));
    }
    for(auto e: edges){
        num[e.f][co[e.s]]++;
        num[e.s][co[e.f]]++;
    }
    if(k >= 2){
        for(auto e: edges){
            if(co[e.f] != co[e.s]){
                res[2] += 2;
            }
        }
    }
    if(k >= 3){
        f0r(i, n){
            f0r(a, k){
                f0r(b, k){
                    if(a!= b && a!= co[i] && b != co[i]){
                        res[3] += num[i][a]*num[i][b];
                    }
                }
            }
        }
    }
    if(k>= 4){
        for(auto e: edges){
            f0r(a, k){
                f0r(b, k){
                    set<int> s;
                    s.insert(a);
                    s.insert(b);
                    s.insert(co[e.f]);
                    s.insert(co[e.s]);
                    if(sz(s) == 4){
                        res[4] += 2*num[e.f][a]*num[e.s][b];
                    }
                }
            }
        }
    }
    f0r(a, 4){
        f0r(b, 4){
            f0r(c, 4){
                f0r(d, 4){
                    set<int> s;
                    s.insert(a);
                    s.insert(b);
                    s.insert(c);
                    s.insert(d);
                    if(sz(s) == 4){
                        vi tmp;
                        tmp.eb(a);
                        tmp.eb(b);
                        tmp.eb(c);
                        tmp.eb(d);
                        states.eb(tmp);
                    }
                }
            }
        }
    }
    if(k >= 5){
        f0r(i, n){
            f0r(a, 5) f0r(b, 5) cnt[a][b] = 0;
            for(int nxt: adj[i]){
                f0r(j, 5){
                    cnt[co[nxt]][j] += num[nxt][j];
                }
            }
            vi colors;
            f0r(j, 5) if(j != co[i]) colors.eb(j);
            for(auto v: states){
                int a = colors[v[0]];
                int b = colors[v[1]];
                int c = colors[v[2]];
                int d = colors[v[3]];
                res[5] += cnt[a][b]*cnt[c][d];
            }

        }
    }
    ll ans = 0;
    f1r(i, 2, k+1) ans += res[i];
    cout << ans << endl;
    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

paths.cpp:1: warning: ignoring #pragma comment  [-Wunknown-pragmas]
    1 | #pragma comment(linker, "/stack:200000000")
      | 
paths.cpp: In function 'void io(std::string)':
paths.cpp:52:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   52 |     freopen(FIN, "r", stdin);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~
paths.cpp:53:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   53 |     freopen(FOUT, "w", stdout);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~~~

• Subtask 1: 23 / 23
• Subtask 2: 20 / 20
• Subtask 3: 27 / 27
• Subtask 4: 30 / 30