이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
#define pb emplace_back
#define AI(i) begin(i), end(i)
template<class T>
bool chmax(T &val, T nv) {
return val < nv ? (val = nv, true) : false;
}
template<class T>
bool chmin(T &val, T nv) {
return nv < val ? (val = nv, true) : false;
}
using namespace std;
using ll = long long;
#ifdef KEV
#define DE(args...) kout("[ " + string(#args) + " ] = ", args)
void debug(auto L, auto R) { while (L < R) cerr << *L << " \n"[L+1==R], ++L; }
void kout(){ cerr << endl; }
template<class T1, class ...T2> void kout(T1 a, T2 ...e) { cerr << a << ' ', kout(e...); }
#else
#define DE(...) 0
#define debug(...) 0
#endif
// What I should check
// 1. overflow
// 2. corner cases
// Enjoy the problem instead of hurrying to AC
// Good luck !
const int MAX_N = 300010;
int n, a[MAX_N], on[MAX_N], res[MAX_N], nxt[MAX_N];
set<int> alive;
void toggle(int t) {
if (alive.count(t)) alive.erase(t);
else alive.insert(t);
}
int qry() { return alive.empty() ? 0 : a[*alive.rbegin()]; }
int32_t main() {
ios_base::sync_with_stdio(0), cin.tie(0);
cin >> n;
for (int i = 1;i <= n;++i)
cin >> a[i];
for (int i = 1;i <= n;++i) {
nxt[i] = -1;
if (a[i] > 0) {
toggle(i);
}
else {
for (int j = i - 1;j > 0;--j) if (on[j] && a[i] < a[j]) {
nxt[i] = j;
for (int x = j; x != -1 ;x = nxt[x]) {
if (nxt[x] != -1) assert(on[x] ^ on[ nxt[x] ]);
on[x] ^= 1;
if (a[x] > 0) toggle(x);
}
break;
}
assert(nxt[i] != -1);
}
res[i] = qry();
on[i] = true;
}
for (int i = 1;i <= n;++i)
cout << res[i] << '\n';
}
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