이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define FASTIO ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define pii pair<int, int>
#define ff first
#define ss second
#define PI acos(-1)
#define ld long double
const int mod = 1e9+7, N = 100005, inf = 1e18;
int msb(int val){return sizeof(int)*8-__builtin_clzll(val);}
int a[N], n, m, k;
vector<pii> dp[N];
int pr[N];
vector<int> pm[N];
void solve(int test_case){
int i, j;
cin >> n;
for(i=1;i<=n;i++){
cin >> a[i];
pr[i]=a[i];pr[i]+=pr[i-1];
}
for(i=1;i<=n;i++){
dp[i].pb({pr[i], 1});
dp[i].pb({inf, -213234684});
pm[i].pb(dp[i][0].ss);
for(j=1;j<dp[i].size();j++)pm[i].pb(max(pm[i].back(), dp[i][j].ss));
}
for(i=2;i<=n;i++){
for(j=1;j<i;j++){
int s = pr[i]-pr[j];
int pos = upper_bound(all(dp[j]), pii{s+1,-1})-dp[j].begin();pos--;
if(pos<0)continue;
int mx = pm[j][pos];
dp[i].pb({s, mx+1});
}sort(all(dp[i]));
pm[i].clear();
pm[i].pb(dp[i][0].ss);
for(j=1;j<dp[i].size();j++)pm[i].pb(max(pm[i].back(), dp[i][j].ss));
}
int ans = 1;
for(auto [x, y] : dp[n]){
ans = max(ans, y);
}
cout << ans << '\n';
return;
}
signed main(){
FASTIO;
#define MULTITEST 0
#if MULTITEST
int ___T;
cin >> ___T;
for(int T_CASE = 1; T_CASE <= ___T; T_CASE++)
solve(T_CASE);
#else
solve(1);
#endif
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
segments.cpp: In function 'void solve(long long int)':
segments.cpp:29:12: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<std::pair<long long int, long long int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
29 | for(j=1;j<dp[i].size();j++)pm[i].pb(max(pm[i].back(), dp[i][j].ss));
| ~^~~~~~~~~~~~~
segments.cpp:41:12: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<std::pair<long long int, long long int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
41 | for(j=1;j<dp[i].size();j++)pm[i].pb(max(pm[i].back(), dp[i][j].ss));
| ~^~~~~~~~~~~~~
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