이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "tickets.h"
#include <algorithm>
#include <cassert>
#include <vector>
#include <set>
long long find_maximum(int numRounds, std::vector<std::vector<int>> ticket) {
int numColors = ticket.size();
int numRanks = ticket[0].size();
auto plusCount = std::vector<int>(numColors, 0);
auto minusCount = std::vector<int>(numColors, 0);
for (int color = 0; color < numColors; ++color) {
if (color % 2 == 0)
plusCount[color] = numRounds;
else
minusCount[color] = numRounds;
}
auto getPlusToMinus = [&](int color) -> int {
assert(plusCount[color] > 0);
int plusValue = ticket[color][numRanks - 1 - (plusCount[color] - 1)];
int minusValue = ticket[color][minusCount[color]];
return -(plusValue + minusValue);
};
auto getMinusToPlus = [&](int color) -> int {
assert(minusCount[color] > 0);
int plusValue = ticket[color][numRanks - 1 - plusCount[color]];
int minusValue = ticket[color][minusCount[color] - 1];
return plusValue + minusValue;
};
auto plusToMinus = std::set<std::pair<int, int>>();
auto minusToPlus = std::set<std::pair<int, int>>();
for (int color = 0; color < numColors; ++color) {
if (minusCount[color] > 0) {
minusToPlus.insert({-getMinusToPlus(color), color}); // want largest one
}
if (plusCount[color] > 0) {
plusToMinus.insert({-getPlusToMinus(color), color}); // want smallest one
}
}
while (true) {
// Iterate over the set of feasible solutions,
// and do swaps as long as they are net profitable.
auto minusToPlusItem = *minusToPlus.begin();
auto plusToMinusItem = *plusToMinus.begin();
// Step 1: Erase all items that involve the two colors.
minusToPlus.erase(minusToPlusItem);
if (plusCount[minusToPlusItem.second] > 0)
plusToMinus.erase({-getPlusToMinus(minusToPlusItem.second), minusToPlusItem.second});
plusToMinus.erase(plusToMinusItem);
if (minusCount[plusToMinusItem.second] > 0)
minusToPlus.erase({-getMinusToPlus(plusToMinusItem.second), plusToMinusItem.second});
// Step 2: Check if doing the swap is profitable.
minusToPlusItem.first = -minusToPlusItem.first;
plusToMinusItem.first = -plusToMinusItem.first;
if (minusToPlusItem.first + plusToMinusItem.first <= 0)
break;
// Step 3: Do the swap.
int color1 = minusToPlusItem.second;
int color2 = plusToMinusItem.second;
minusCount[color1]--;
plusCount[color1]++;
minusCount[color2]++;
plusCount[color2]--;
// Step 4: Update the data structures with the new swap candidates.
for (int color : {color1, color2}) {
if (minusCount[color] > 0) {
minusToPlus.insert({-getMinusToPlus(color), color}); // want largest one
}
if (plusCount[color] > 0) {
plusToMinus.insert({-getPlusToMinus(color), color}); // want smallest one
}
}
}
long long res = 0;
for (int color = 0; color < numColors; ++color) {
assert(plusCount[color] + minusCount[color] == numRounds);
for (int index = 0; index < minusCount[color]; ++index) res -= ticket[color][index];
for (int index = 0; index < plusCount[color]; ++index) res += ticket[color][numRanks - 1 - index];
}
auto answer = std::vector<std::vector<int>>(numColors, std::vector<int>(numRanks, -1));
auto countPerRound = std::vector<std::pair<int, int>>();
for (int round = 0; round < numRounds; ++round) countPerRound.push_back({0, round});
// Step 5: Construct the actual assignment of tickets.
auto plusColors = std::vector<int>(numColors);
for (int color = 0; color < numColors; ++color) plusColors[color] = color;
for (int round = 0; round < numRounds; ++round) {
std::sort(plusColors.begin(), plusColors.end(), [&](int lhs, int rhs) -> bool {
return plusCount[lhs] > plusCount[rhs];
});
auto marked = std::vector<bool>(numColors, false);
for (int index = 0; index < numColors / 2; ++index) {
int color = plusColors[index];
assert(plusCount[color] > 0);
answer[color][numRanks - 1 - (plusCount[color] - 1)] = round;
--plusCount[color];
marked[color] = true;
}
for (int color = 0; color < numColors; ++color) if (!marked[color]) {
assert(minusCount[color] > 0);
answer[color][minusCount[color] - 1] = round;
--minusCount[color];
}
}
allocate_tickets(answer);
return res;
}
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