Submission #334305

#	Time	Username	Problem	Language	Result	Execution time	Memory
334305		HoneyBadger	Growing Vegetable is Fun 3 (JOI19_ho_t3)	C++17	100 / 100	294 ms	202744 KiB

joi2019_ho_t3

#include <iostream>
#include <iomanip>
#include <cstdio>
#include <vector>
#include <bitset>
#include <string>
#include <cstring>
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <deque>
#include <utility>
#include <algorithm>
#include <random>
#include <cmath>
#include <cassert>
#include <climits>
#include <ctime>
#include <chrono>



#pragma GCC optimize("Ofast")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,sse4.1,sse4.2,popcnt,abm,mmx,avx,avx2,tune=native")



#ifdef LOCAL
    #define dbg(x) cout << #x << " : " << x << endl;
#else
    #define dbg(x)
#endif


#define pb push_back
#define ppb pop_back()
#define mp make_pair
#define fi(a, b) for (int i = a; i < b; i++)
#define fj(a, b) for (int j = a; j < b; j++)
#define fk(a, b) for (int k = a; k < b; k++)
#define fi1(a, b) for (int i = a - 1; i >= b; i--)
#define fj1(a, b) for (int j = a - 1; j >= b; j--)
#define fk1(a, b) for (int k = a - 1; k >= b; k--)
#define fx(x, a) for (auto& x : a)
#define rep(i, a, b) for (int i = a; i < b; ++i)
#define rep1(i, a, b) for (int i = a - 1; i >= b; --i)
#define siz(x) (int)x.size()
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

using namespace std;

template<typename T1, typename T2>inline void mine(T1 &x, const T2 &y) { if (y < x) x = y; }
template<typename T1, typename T2>inline void maxe(T1 &x, const T2 &y) { if (x < y) x = y; }

ostream& operator << (ostream &out, const vector<int> &b) {
    for (auto k : b) out << k << ' ';
    return out;
}

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef char ch;
typedef string str;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<pii> vpii;
typedef vector<vpii> vvpii;
typedef vector<ch> vch;
typedef vector<vch> vvch;
typedef vector<str> vs;



const int MOD = 1000000007;
const int INF = 1000000050;
const long long BIG = (long long)2e18 + 50;
#ifdef LOCAL
    const int MX = 20;
#else
	const int MX = 410;
#endif
const double EPS = 1e-9;


mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

int n;
int cnt[MX][3];

int dp[MX][MX / 2][MX / 2][3];  // pref cur0 cur1 last
int p[3];
int np[3];
vi in[3];

int32_t main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    cin >> n;
    vi a(n);
    fx(x, a) {
    	char c;
    	cin >> c;
    	if (c == 'R')
    		x = 0;
    	else if (c == 'G')
    		x = 1;
    	else
    		x = 2;
    }
    fi(1, n + 1) {
    	fj(0, 3) {
    		cnt[i][j] = cnt[i - 1][j]; 
    	}
    	cnt[i][a[i - 1]]++;
        in[a[i - 1]].pb(i - 1);
    }
    fj(0, 3) {
    	if (cnt[n][j] > (n + 1) / 2) {
    		cout << "-1\n";
    		return 0;
    	}
    }
    vi c(3);
 	c[0] = cnt[n][0];
 	c[1] = cnt[n][1];
 	c[2] = cnt[n][2];

    fi(0, MX) fj(0, MX / 2) fk(0, MX / 2) for (int l = 0; l < 3; ++l) dp[i][j][k][l] = INF;
   	for (int l = 0; l < 3; ++l) dp[0][0][0][l] = 0;
    fi(0, n) {
    	int b0 = min(c[0], i);
    	int b1 = min(c[1], i);
    	for (p[0] = 0; p[0] <= b0; ++p[0]) {
    		for (p[1] = 0; p[1] <= b1; ++p[1]) {
    			p[2] = i - p[0] - p[1];
    			if (p[2] < 0 || p[2] > c[2]) continue; 
    			memcpy(np, p, sizeof(p));
    			for (int l = 0; l < 3; ++l) {
    				if (i && !p[l]) continue;
    				for (int l2 = 0; l2 < 3; ++l2) {
    					if (l2 == l || p[l2] == c[l2]) continue;
    					np[l2]++;
                        int j = in[l2][p[l2]];
    					int delta = 0;
    					for (int col = 0; col < 3; ++col) {
    					   if (col != l2) {
                                delta += max(0, cnt[j][col] - p[col]);
                           }
                        }
                        mine(dp[i + 1][np[0]][np[1]][l2], dp[i][p[0]][p[1]][l] + delta);
    					np[l2]--;
    				}
    			} 
    		}
    	}
    }
    int ans = INF;
    for (int l = 0; l < 3; ++l) {
    	mine(ans, dp[n][c[0]][c[1]][l]);
    }
    assert(ans != INF);
    cout << ans << '\n';
}

• Subtask 1: 5 / 5
• Subtask 2: 55 / 55
• Subtask 3: 15 / 15
• Subtask 4: 25 / 25