Submission #333248

#TimeUsernameProblemLanguageResultExecution timeMemory
333248aloo123Factories (JOI14_factories)C++14
0 / 100
2880 ms102124 KiB
#include <bits/stdc++.h> #include "factories.h" using namespace std; using ll = long long; using pl = pair<ll,ll>; using vl = vector<ll>; #define mp make_pair #define f first #define s second // vectors #define sz(x) (int)(x).size() #define all(x) begin(x), end(x) #define ins insert #define pf push_front #define pb push_back // loops #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define F0R(i,a) FOR(i,0,a) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) #define R0F(i,a) ROF(i,0,a) #define trav(a,x) for (auto& a: x) const int MOD = 1e9+7; // 998244353; const int INF = 1e9; // not too close to LLONG_MAX // #define int ll const int xd[4] = {1,0,-1,0}, yd[4] = {0,1,0,-1}; // for every grid problem!! const int MAXN = 1e6+5; const int LOGN = 25; int n,current_tree = 0; vector<pl> g[MAXN]; int best[MAXN],deleted[MAXN]; int depth[MAXN]; int par[MAXN],sub[MAXN]; int dist[LOGN][MAXN]; // initally all nodes are red int LCA(int u,int v){ // finds LCA in of u and v in the centroid tree while(u != v){ if(depth[u] < depth[v]) v = par[v]; // get v a level up else u = par[u]; // get u a level up } return u; } int compute_dist(int x,int y){ int lc = depth[LCA(x,y)]; return dist[lc][x] + dist[lc][y]; } void find_subtree(int u,int p){ sub[u] = 1; current_tree++; trav(P,g[u]){ int v = P.f; if(deleted[v] == 0 && v != p){ find_subtree(v,u); sub[u] += sub[v]; } } } int find_centroid(int u,int p){ trav(P,g[u]){ int v = P.f; if(deleted[v] == 0 && v !=p && sub[v] > (current_tree / 2)) return find_centroid(v,u); } return u; } void dfs(int u,int p,int lvl,int dd){ dist[lvl][u] = dd; trav(P,g[u]){ int v = P.f; int w = P.s; if(deleted[v] == 0 && v != p){ dfs(v,u,lvl,dd + w); } } } void decompose(int root,int p){ current_tree = 0; find_subtree(root,p); int cen = find_centroid(root,p); par[cen] = p; if(p != -1) depth[cen] = depth[p] + 1; dfs(cen,p,depth[cen],0); deleted[cen] = 1; trav(P,g[cen]){ int v = P.f; if(deleted[v] == 1) continue; decompose(v,cen); } } int query(int u){ // find the nearest blue node to u int ans = best[u]; int x = u; u = par[u]; while(u != -1){ ans = min(ans,compute_dist(x,u) + best[u]); u = par[u]; } return ans; } void update(int u){ // colour node u to blue int x = u; while(u != -1){ best[u] = min(best[u],compute_dist(u,x)); u = par[u]; } } void remove_col(int u){ // u has to be a blue node // remove its colour while(u != -1){ best[u] = INF; u = par[u]; } } void Init(int N, int A[], int B[], int D[]) { n = N; FOR(i,0,n-1){A[i]++,B[i]++; g[A[i]].pb(mp(B[i],D[i])); g[B[i]].pb(mp(A[i],D[i])); } for(int i =1;i<=n;i++) best[i] = INF; decompose(1,-1); } long long Query(int S, int X[], int T, int Y[]) { for(int i =0;i<S;i++) X[i]++; for(int i =0;i<T;i++) Y[i]++; for(int i = 0;i < T;i++){ update(Y[i]); } int ans = INF; for(int i = 0;i< S;i++){ ans = min(ans,query(X[i])); } for(int i =0;i<T;i++){ remove_col(Y[i]); } return ans; } /* void solve(){ cin >> n; int q; cin >> q; FOR(i,2,n+1){ int u,v,w; cin >> u >> v >> w; u++,v++; g[u].pb(mp(v,w)); g[v].pb(mp(u,w)); } for(int i =1;i<=n;i++) best[i] = INF; decompose(1,-1); FOR(i,1,n+1){ cout << i << " " << par[i] << endl; } while(q--){ int s,t; cin >> s >> t; vl u(s),v(t); for(int i =0;i<s;i++) cin >> u[i],u[i]++; for(int i =0;i<t;i++) cin >> v[i],v[i]++; for(int i = 0;i < t;i++){ update(v[i]); } int ans = INF; for(int i = 0;i< s;i++){ ans = min(ans,query(u[i])); } cout << ans << endl; for(int i =0;i<t;i++){ remove_col(v[i]); } } } signed main() { cin.tie(0)->sync_with_stdio(0); // you should actually read the stuff at the bottom int t=1; // cin >> t; while(t--){ solve(); } } */ /* stuff you should look for * read the probem 3 more times in case of WA :) * int overflow, array bounds * special cases (n=1?) * do smth instead of nothing and stay organized * WRITE STUFF DOWN * DON'T GET STUCK ON ONE APPROACH */
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